QUESTION 23 Using the calibration curve below (equation of the line: y=0.0039x + 0.9981) to determine the percentage of sugar in a sugar water solution with a density of 1.034 g/mL. Density versus Percent Sugar 1.07 1.06 y = 0.0039x + 0.9981 R= 0.9998 1.05 1.04 1.03 1.02 1.01 0.99 10 12 14 16 Percent Sugar (% m/m ) O 4.2 % O 1.0% O 8.5% 9.9% O 9.2% Density (g/mL)
QUESTION 23 Using the calibration curve below (equation of the line: y=0.0039x + 0.9981) to determine the percentage of sugar in a sugar water solution with a density of 1.034 g/mL. Density versus Percent Sugar 1.07 1.06 y = 0.0039x + 0.9981 R= 0.9998 1.05 1.04 1.03 1.02 1.01 0.99 10 12 14 16 Percent Sugar (% m/m ) O 4.2 % O 1.0% O 8.5% 9.9% O 9.2% Density (g/mL)
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Question 23
**Using the calibration curve below (equation of the line: y=0.0039x + 0.9981) to determine the percentage of sugar in a sugar water solution with a density of 1.034 g/mL.**
### Graph Explanation
The graph shown is titled "Density versus Percent Sugar." It depicts the relationship between the density of a sugar water solution (y-axis) and the percentage of sugar in the solution (x-axis).
- **x-axis (independent variable):** Percentage of sugar (% m/m) ranging from 0% to 15%.
- **y-axis (dependent variable):** Density (g/mL) ranging from 0.99 g/mL to 1.07 g/mL.
Four data points are plotted on the graph, and a linear trendline is fitted to these points. The equation of the trendline is provided as:
\[ y = 0.0039x + 0.9981 \]
The R² value of 0.9998 indicates a very high correlation between density and percentage of sugar, implying that the linear model is an excellent fit for the data.
### Calculation
To determine the percentage of sugar in a solution with a given density (1.034 g/mL), use the equation of the line provided:
\[ y = 0.0039x + 0.9981 \]
Given that y (density) = 1.034 g/mL, solve for x (percentage of sugar):
\[ 1.034 = 0.0039x + 0.9981 \]
Subtract 0.9981 from both sides:
\[ 1.034 - 0.9981 = 0.0039x \]
\[ 0.0359 = 0.0039x \]
Solve for x by dividing both sides by 0.0039:
\[ x = \frac{0.0359}{0.0039} \]
\[ x = 9.2 \% m/m \]
Therefore, a sugar water solution with a density of 1.034 g/mL contains approximately 9.2% sugar by mass.
**Answer Choices:**
- 4.2%
- 1.0%
- 8.5%
- 9.9%
- 9.2%
Based on the calculation, the correct answer is **9.2%**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4b643de3-db86-4776-bab8-d91fe7c88bba%2F2a914de3-9ff9-4721-b423-8432e001932e%2Fwz2htvj_processed.png&w=3840&q=75)
Transcribed Image Text:### Question 23
**Using the calibration curve below (equation of the line: y=0.0039x + 0.9981) to determine the percentage of sugar in a sugar water solution with a density of 1.034 g/mL.**
### Graph Explanation
The graph shown is titled "Density versus Percent Sugar." It depicts the relationship between the density of a sugar water solution (y-axis) and the percentage of sugar in the solution (x-axis).
- **x-axis (independent variable):** Percentage of sugar (% m/m) ranging from 0% to 15%.
- **y-axis (dependent variable):** Density (g/mL) ranging from 0.99 g/mL to 1.07 g/mL.
Four data points are plotted on the graph, and a linear trendline is fitted to these points. The equation of the trendline is provided as:
\[ y = 0.0039x + 0.9981 \]
The R² value of 0.9998 indicates a very high correlation between density and percentage of sugar, implying that the linear model is an excellent fit for the data.
### Calculation
To determine the percentage of sugar in a solution with a given density (1.034 g/mL), use the equation of the line provided:
\[ y = 0.0039x + 0.9981 \]
Given that y (density) = 1.034 g/mL, solve for x (percentage of sugar):
\[ 1.034 = 0.0039x + 0.9981 \]
Subtract 0.9981 from both sides:
\[ 1.034 - 0.9981 = 0.0039x \]
\[ 0.0359 = 0.0039x \]
Solve for x by dividing both sides by 0.0039:
\[ x = \frac{0.0359}{0.0039} \]
\[ x = 9.2 \% m/m \]
Therefore, a sugar water solution with a density of 1.034 g/mL contains approximately 9.2% sugar by mass.
**Answer Choices:**
- 4.2%
- 1.0%
- 8.5%
- 9.9%
- 9.2%
Based on the calculation, the correct answer is **9.2%**
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