Using the calibration curve below (equation of the line: y=0.0039x + 0.9981) to determine the percentage of sugar in a sugar water solution with a density of 1.034 g/mL. Density versus Percent Sugar 1.07 1.06 y = 0.0039x + 0.9981 R= 0.9998 1.05 1.04 1.03 1.02 1.01 1 0.99 4. 6 8 10 12 14 16 Percent Sugar (% m/m ) 8.5% 1.0% 9.2% 4.2 % 9.9% Density (g/mL)

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## Determining the Percentage of Sugar in a Sugar Water Solution

### Using the Calibration Curve

To determine the percentage of sugar in a sugar water solution with a known density of 1.034 g/mL, we can use the provided calibration curve. The equation of the line depicted in the calibration curve is:

\[ y = 0.0039x + 0.9981 \]
\[ R^2 = 0.9998 \]

Where:
- \( y \) represents the density (g/mL)
- \( x \) represents the percent sugar (% m/m)

### Graph Description: Density versus Percent Sugar

The graph "Density versus Percent Sugar" plots density (in g/mL) on the y-axis and the percent sugar (in % m/m) on the x-axis. Four marked points on the graph indicate measured data, and a trend line is fitted to these points with the given linear equation.

- The graph ranges from 0% to 15% sugar on the x-axis.
- On the y-axis, density ranges from 0.99 g/mL to 1.07 g/mL.
- The plotted data points lie close to the trend line, illustrating a direct linear relationship between density and sugar concentration, hence a high \( R^2 \) value of 0.9998, indicating an excellent fit of the line to the data.

### Calculation Example

Given a solution density of 1.034 g/mL, we can use the equation to find the corresponding percentage of sugar:

\[ 1.034 = 0.0039x + 0.9981 \]

Solving for \( x \):

1. Subtract 0.9981 from both sides:
   \[ 1.034 - 0.9981 = 0.0039x \]
   \[ 0.0359 = 0.0039x \]

2. Divide both sides by 0.0039:
   \[ x = \frac{0.0359}{0.0039} \]
   \[ x \approx 9.21 \]

Thus, the percentage of sugar in the sugar water solution with a density of 1.034 g/mL is approximately **9.2%**.
Transcribed Image Text:## Determining the Percentage of Sugar in a Sugar Water Solution ### Using the Calibration Curve To determine the percentage of sugar in a sugar water solution with a known density of 1.034 g/mL, we can use the provided calibration curve. The equation of the line depicted in the calibration curve is: \[ y = 0.0039x + 0.9981 \] \[ R^2 = 0.9998 \] Where: - \( y \) represents the density (g/mL) - \( x \) represents the percent sugar (% m/m) ### Graph Description: Density versus Percent Sugar The graph "Density versus Percent Sugar" plots density (in g/mL) on the y-axis and the percent sugar (in % m/m) on the x-axis. Four marked points on the graph indicate measured data, and a trend line is fitted to these points with the given linear equation. - The graph ranges from 0% to 15% sugar on the x-axis. - On the y-axis, density ranges from 0.99 g/mL to 1.07 g/mL. - The plotted data points lie close to the trend line, illustrating a direct linear relationship between density and sugar concentration, hence a high \( R^2 \) value of 0.9998, indicating an excellent fit of the line to the data. ### Calculation Example Given a solution density of 1.034 g/mL, we can use the equation to find the corresponding percentage of sugar: \[ 1.034 = 0.0039x + 0.9981 \] Solving for \( x \): 1. Subtract 0.9981 from both sides: \[ 1.034 - 0.9981 = 0.0039x \] \[ 0.0359 = 0.0039x \] 2. Divide both sides by 0.0039: \[ x = \frac{0.0359}{0.0039} \] \[ x \approx 9.21 \] Thus, the percentage of sugar in the sugar water solution with a density of 1.034 g/mL is approximately **9.2%**.
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