How much 20.0% NaOH should I put in a 30.0 ml tube if my dilution ratio is 1/10. What is the concentration of the tube. ml of 20.0% Just put the number of mL Do not enter anything but a number. Use correct sig figs. Remember ratios and conversion factors do not enter the significant figure calculation. What is the concentration in percent. Again, correct significant figures. NUMBERS only not the % sign

How much 20.0% NaOH should I put in a 30.0 ml tube if my dilution ratio is 1/10. What is the concentration of the tube. ml of 20.0% Just put the number of mL Do not enter anything but a number. Use correct sig figs. Remember ratios and conversion factors do not enter the significant figure calculation. What is the concentration in percent. Again, correct significant figures. NUMBERS only not the % sign

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter4: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 4RQ: Molarity is a conversion factor relating moles of solute in solution to the volume of the solution....

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Similar questions

What does it mean when we say that a 200-mL sample and a 400-mL sample of a solution of salt have the same molarity? In what ways are the two samples identical? In what ways are these two samples different?
Molarity is a conversion factor relating moles of solute in solution to the volume of the solution. How does one use molarity as a conversion factor to convert from moles of solute to volume of solution, and from volume of solution to moles of solute present?
Sulfuric acid is listed in a catalog with a concentration of 95-98%. A bottle of the acid in the stockroom states that 1.00 L has a mass of 1.84 kg. To determine the concentration of sulfuric acid in the stockroom bottle, a student dilutes 5.00 mL to 500. mL She then takes four 10.00-mL samples and titrates each with standardized sodium hydroxide (c = 0.1760 M). (a) What is the average concentration of the diluted sulfuric acid sample? (b) What is the mass percent of H2SO4 in the original bottle of the acid?
A student weighs out a 4.80-g sample of aluminum bromide, transfers it to a 100-mL volumetric flask, adds enough water to dissolve it, and then adds water to the 100-mL mark. What is the molarity of aluminum bromide in the resulting solution?
hy is water an important solvent? Although you have not yet studied water in detail, can you think of some properties of water that make it so important?
What mass of solid NaOH (97.0% NaOH by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 10.0% solution is 1.109 g/mL.
The units of parts per million (ppm) and parts per billion (ppb) are commonly used by environmental chemists. In general, 1 ppm means 1 part of solute for every 106 parts of solution. Mathematically, by mass: ppm=gsolutegsolution=mgsolutekgsolution In the case of very dilute aqueous solutions, a concentration of 1.0 ppm is equal to 1.0 g of solute per 1.0 mL, which equals 1.0 g solution. Parts per billion is defined in a similar fashion. Calculate the molarity of each of the following aqueous solutions. a. 5.0 ppb Hg in H2O b. 1.0 ppb CHCl3 in H2O c. 10.0 ppm As in H2O d. 0.10 ppm DDT (C14H9Cl5) in H2O
What mass of HCl is contained in 45.0 mL of an aqueous HCl solution that has a density of 1.19 g cm-3 and contains 37.21% HCl by mass?
Explain what changes and what stays the same when 1.00 L of a solution of NaCl is diluted to 1.80 L.
Distinguish between the solute and solvent in each of the following solutions: a saltwater [NaCl(aq)]; b sterling silver (92.5%Ag,7.5%Cu); c air about 80%N2,20%O2. On what do you base your distinctions? Sterling silver is an alloy of 92.5 silver and 7.5 another metal, usually copper.
3.65 Determine the final molarity for the following dilutions. (a) 24.5 mL of 3.0 M solution diluted to 100.0 mL (b) 15.3 mL of 4.22 M solution diluted to 1.00 L (c) 1.45 mL of 0.034 M solution diluted to 10.0 mL (d) 2.35 L of 12.5 M solution diluted to 100.0 L
A solution is 0.1% by mass calcium chloride. Therefore, 100. g of the solution contains g of calcium chloride.