155 mL solution X STARTING AMOUNT 155 mL solution x 0.762 mol FeCl 0.762 L solution x 0.762 mol-FECT 0.762 L solution 162.2 g FeCl₂ 162.2 mol FeCl, 0.1 = 6.60 L solution 6.60 If you have 155 mL solution of a 0.762 M FeCl, solution, how many grams of FeCl, are contained in this sample? X 0.762 124 g FeCl, L solution 162.2 g FeCl₂ 162.2 100 0.01 1 Question 6 of 17 molFECT f g Cl M FeCl 25.1 1.92 155 0.118 12.6 7.28 x 10¹ 6.60 35.45 4.92 162.2 mol FeCI/L solution mol FeCl mL solution L solution g Fe³ 2 55.85 0.203 1000 19.2 g FeCl/mol FeCl₂ Submit +

155 mL solution X STARTING AMOUNT 155 mL solution x 0.762 mol FeCl 0.762 L solution x 0.762 mol-FECT 0.762 L solution 162.2 g FeCl₂ 162.2 mol FeCl, 0.1 = 6.60 L solution 6.60 If you have 155 mL solution of a 0.762 M FeCl, solution, how many grams of FeCl, are contained in this sample? X 0.762 124 g FeCl, L solution 162.2 g FeCl₂ 162.2 100 0.01 1 Question 6 of 17 molFECT f g Cl M FeCl 25.1 1.92 155 0.118 12.6 7.28 x 10¹ 6.60 35.45 4.92 162.2 mol FeCI/L solution mol FeCl mL solution L solution g Fe³ 2 55.85 0.203 1000 19.2 g FeCl/mol FeCl₂ Submit +

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 45QAP

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