QUESTION 2To test the effect of a new medication on pulse rate, the researcher randomly selected the 60subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group2, respectively. Below is the Minitab output.Two-Sample T-Test and CIGroup1NМeanStDev7.80SE Mean3065.201.423070.308.401.5Difference = mu (1) - mu (2)Estimate for difference: -5.1095% CI for difference:(-9.29, -0. 91)T-Test of difference = 0 (vs not =): T-Value = -2.44P-Value=0.018DF=57i) State the formula you would use to construct a 95% confidence interval. Include the valueof a and degrees of freedom that you will use to find the critical value in the formula

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Answered: QUESTION 2 To test the effect of a new…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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QUESTION 2 To test the effect of a new medication on pulse rate, the researcher randomly selected the 60 subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group 2, respectively. Below is the Minitab output. Two-Sample T-Test and CI Group Мean StDev SE Mean 1 30 65.20 7.80 1.4 2 30 70.30 8.40 1.5 Difference = mu (1) - mu (2) Estimate for difference: 95% CI for difference: T-Test of difference = 0 (vs not =): T-Value = -2.44 -5.10 (-9.29, -0.91) P-Value=0.018 DF=57 ii) Using to.025,57 = 2.003 shows that the 95% confidence interval for the difference in mean pulse rate between new medication and placebo is (-9.29, -0.91). Hence, interpret its meaning.
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