i) Using to.025.57 = 2.003 shows that the 95% confidence interval for the difference in mean pulse rate between new medication and placebo is (-9.29, -0.91). Hence, interpret its meaning. %3D

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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QUESTION 2
To test the effect of a new medication on pulse rate, the researcher randomly selected the 60
subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group
2, respectively. Below is the Minitab output.
Two-Sample T-Test and CI
Group
Мean
StDev
SE Mean
1
30
65.20
7.80
1.4
2
30
70.30
8.40
1.5
Difference = mu (1) - mu (2)
Estimate for difference:
95% CI for difference:
T-Test of difference = 0 (vs not =): T-Value = -2.44
-5.10
(-9.29, -0.91)
P-Value=0.018
DF=57
ii) Using to.025,57 = 2.003 shows that the 95% confidence interval for the difference in mean
pulse rate between new medication and placebo is (-9.29, -0.91). Hence, interpret its
meaning.
Transcribed Image Text:QUESTION 2 To test the effect of a new medication on pulse rate, the researcher randomly selected the 60 subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group 2, respectively. Below is the Minitab output. Two-Sample T-Test and CI Group Мean StDev SE Mean 1 30 65.20 7.80 1.4 2 30 70.30 8.40 1.5 Difference = mu (1) - mu (2) Estimate for difference: 95% CI for difference: T-Test of difference = 0 (vs not =): T-Value = -2.44 -5.10 (-9.29, -0.91) P-Value=0.018 DF=57 ii) Using to.025,57 = 2.003 shows that the 95% confidence interval for the difference in mean pulse rate between new medication and placebo is (-9.29, -0.91). Hence, interpret its meaning.
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