1 Question 2:2 The composite beam consists of a wood core and two plates of steel. If the allowable bending3 stress for the wood is (ae = 20MPA1 for the steel4 determine the maximum moment that can be applied to the beam.E =11G Pa, E„ = 200G Pa(o = 130MPA567 Take:A =B = 808130mmA mmmm1011M1220 mm13B mm1420 mm151617 Solution:E 200(1on =18= 18.18219E.1100)20 The width of steel rpt be increased to an equivalent width for wood:21mm2223| =-width (A) =(10) m*122425 Failure of wood:26Mc27(O. ma280.5MA20(10 )=29M =kNm3031 Failure of steel:nMc32(o.)ar 'man33(18.182)(0.5 MA)34130(10)=M =kNmAns353637383940414243

Composite beam: The combination of one or more materials together in order to increase the stiffness…

Question 2: The composite beam consists of a wood core and two plates of steel. If the allowable bending stress for the wood is (o)= 20MPai for the steel determine the maximum moment that can be applied to the beam. E =11G Pa, E = 200G Pa (0lle = 130MPA Take: A = 130 mm A mm B = 80 mm M 20 mm B mm 20 mm Solution: 200(10') =18.182 1100') The width of steel rpt be increased to an equivalent width for wood: mm ar |=-w idth (A) (10) m 12 Failure of wood: Mc (0. 0.5MA 20(10) M = kNm Failure of steel: nMc (O'mas (18.182)(0.5 MA) 130(10) = M = kNm Ans

Question 2: The composite beam consists of a wood core and two plates of steel. If the allowable bending stress for the wood is (o)= 20MPai for the steel determine the maximum moment that can be applied to the beam. E =11G Pa, E = 200G Pa (0lle = 130MPA Take: A = 130 mm A mm B = 80 mm M 20 mm B mm 20 mm Solution: 200(10') =18.182 1100') The width of steel rpt be increased to an equivalent width for wood: mm ar |=-w idth (A) (10) m 12 Failure of wood: Mc (0. 0.5MA 20(10) M = kNm Failure of steel: nMc (O'mas (18.182)(0.5 MA) 130(10) = M = kNm Ans

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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