Question 2 For a graph G on vertex set X and a vertex v E X, we define G - v to be the induced subgraph of G with vertex set X – {v}. We say that a graph G is doubly connected if for all vertices v, G Let G be a simple graph. Prove that G is doubly connected if and only if for all vertices u, v and w there is a path from u to v which does not go through w. | v is connected.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Question 2 For a graph G on vertex set X and a vertex v E X, we define
G – v to be the induced subgraph of G with vertex set X – {v}. We say that a
graph G is doubly connected if for all vertices v, G – v is connected.
Let G be a simple graph. Prove that G is doubly connected if and only if for
all vertices u, v and w there is a path from u to v which does not go through w.
|
Transcribed Image Text:Question 2 For a graph G on vertex set X and a vertex v E X, we define G – v to be the induced subgraph of G with vertex set X – {v}. We say that a graph G is doubly connected if for all vertices v, G – v is connected. Let G be a simple graph. Prove that G is doubly connected if and only if for all vertices u, v and w there is a path from u to v which does not go through w. |
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