Suppose that an edge e ::= {v1, v2 } is on a cycle in a graph G where v1, v2 are vertices of G. If e is removed from G to create the graph G e, then there exists a path from v1 to v2 in G – e. If e is removed from G to create the graph G e, then there does not exist a path from v1 to v2 in G – e. O If e is removed from G to create the graph G - e, then it is not possible to determine if there exists a path from vị to v2 in G – e.
Suppose that an edge e ::= {v1, v2 } is on a cycle in a graph G where v1, v2 are vertices of G. If e is removed from G to create the graph G e, then there exists a path from v1 to v2 in G – e. If e is removed from G to create the graph G e, then there does not exist a path from v1 to v2 in G – e. O If e is removed from G to create the graph G - e, then it is not possible to determine if there exists a path from vị to v2 in G – e.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Suppose that an edge e ::= {v1, V2} is on a cycle in a graph G where v1, v2 are vertices of G.
If e is removed from G to create the graph G
e, then there exists a path from vị to v2 in G – e.
If e is removed from G to create the graph G
- e, then there does not exist a path from v1 to v2 in G – e.
If e is removed from G to create the graph G – e, then it is not possible to determine if there exists a path
from vị to v2 in G – e.
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