Q8. In the inverted crank-slider shown, link 2 is the input and link 4 is the output.If 0₂0₁= 27 cm and O₂A = 18 cm, then the total swinging angle of link 4 about O, isfound to be:a) 45°b) 72.3⁰c) 83.6°d) 89.4°e) 60° f) None of the aboveQ9. The time ratio of this mechanism is found to be:a) 1.828b) 3.344c) 2.735 d) 1.5 e) 2.115 f) None of the aboveОАQ10. Assume that in the position shown, link 2 rotates at 10 rad/s hence causing link 4 torotate at 4 rad/s. If the torque on link 2 is 100 N.m, then by neglecting power losses, thetorque on link 4 is:c) 500 N.ma) 250 N.mb) 375 N.md) 650 N.me) None of the above.rosIm]3ARe

we have to determine the total swing angle of link 4 about O4

Q8. In the inverted crank-slider shown, link 2 is the input and link 4 is the output. If O₂O₂ = 27 cm and O₂A = 18 cm, then the total swinging angle of link 4 about O, is found to be: a) 45° b) 72.3° b) 72.3⁰ c) 83.6° d) 89.4⁰ e) 60° f) None of the above

Q8. In the inverted crank-slider shown, link 2 is the input and link 4 is the output. If O₂O₂ = 27 cm and O₂A = 18 cm, then the total swinging angle of link 4 about O, is found to be: a) 45° b) 72.3° b) 72.3⁰ c) 83.6° d) 89.4⁰ e) 60° f) None of the above

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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