Replace the force system by an equivalent resultant force and couple moment at point 0. B) = 359 N M=3180 N.m 62.8° 130 N 12 62.8° 15 13 M=3180 N.m E) = 359 N FR = 359 N FR 6 m 4 m 62.8° 1 m 1 m D) M=3180 N.m M=3180 N.m 53° M=3180 N.m - 2 m- 62.8° 62.8° 500 N *R = 359 N = 359 N R What is the resultant force and moment?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Replace the force system by an equivalent resultant force
and couple moment at point O.
A)
B)
= 359 N
R
M=3180 N.m
62.8°
12
62.8°
130 N
M=3180 N.m
13
= 359 N
E)
= 359 N
FR
6 m
4 m
62.8°
C)
1 m
1 m
D)
M=3180 N.m
M=3180 N.m
M=3180 N.m
53°
+2 m-
62.8°
62.8°
500 N
= 359 N
FR
= 359 N
What is the resultant force and moment?
Transcribed Image Text:Replace the force system by an equivalent resultant force and couple moment at point O. A) B) = 359 N R M=3180 N.m 62.8° 12 62.8° 130 N M=3180 N.m 13 = 359 N E) = 359 N FR 6 m 4 m 62.8° C) 1 m 1 m D) M=3180 N.m M=3180 N.m M=3180 N.m 53° +2 m- 62.8° 62.8° 500 N = 359 N FR = 359 N What is the resultant force and moment?
Expert Solution
Step 1

Force in X- direction is -FX =500cos53° - 130×1213FX =180.9 NForce in Y- direction is -FX =-500sin53° + 130×513FX =349.3 NNet force will be - Fnet = FX2 + FY2Fnet = 180.92 + -349.32Fnet =393.3 NFnet 359 NThe angle of resultant force will be - θ = tan-1-349.3180.9θ = -62.63°θ- 62.8°The negative sign shows that the resultant force wil be at clockwise 62.8° from X-axis.

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