Z.F1 = 500 N4 mO A) 400 kF3O B) 400j3 myC) 400 i+400 j2 mF2 = 400 NO D) 400j+400 kF3 = {-200i + 500j – 300k} N.%3DE) - 400 iExpress the force F, in vector form.

Given: F1=500NF2=400NF3=-200i^+500j^-300k^

Answered: F1 = 500 N 4 m O A) 400 k B) 400 j 3 m…

F1 = 500 N 4 m O A) 400 k B) 400 j 3 m y O 9 400 i +400 j 2 m F2 = 400 N O D) 400 j+400 k F; = {-200i + 500j – 300k} N. E) - 400 i Express the force F, in vector form.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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F1 = 3 kN F2 = 11 kN B - 30° C. F3 = 2 kN 60 A 2 m 7m E F4 = 20 kN D Ela 30 F5 = 2 kN 1] What is the resultant moment of the five forces acting on the rod about point B? a) 17.8 kN.m b) 20.4 kN.m c) 10.6 kN.m d) 12.9 kN.m e) 27.1 kN.m ) 30.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point E? a) – 21.7 kN.m b) -11.1 kN.m c) - 4.8 kN.m d) - 9.1 kN.m e) - 17.1 kN.m 9 -27.3 kN.m 3] What is the moment of the force F1 about point D? a) - 5.8 kN.m b) - 21.2 kN.m c) - 25.6 kN.m d) - 9.9 kN.m e) 1- 8.1 kN.m ) - 26.1 kN.m 4] What is the moment of the force F2 about point E? a) 66.8 kN.m b) 25.4 kN.m e) 43.6 kN.m d) 62.9 kN.m e) 58.6 kN.m ) 23.1 kN.m Activate Windows 5] What is the moment of the force F5 about point B? Go to Settings to activate Wi e) - 11.1 kN.m a) - 19.7 kN.m b) -6.7 kN.m c) - 4.8 kN.m d) - 9.1 kN.m ) -2.3 kN.m
D. C. F3 B. F4 Consider the following values: FS a-25 m; b 5 m; c 25 m; d-5 m; F1-7 kN; F2 8 kN; F3 - 9 kN; F4 -10 kN; F5 11 kN; 1] What is the resultant moment of the five forces acting on the rod about point A? a)-158 kN.m c) 146 kN.m d) - 103 kN.m e) 241 kN.m NA ILI -G 21 What is the resultant moment of the five forces acting on the rod about point B? a) 98.8 kN.m b)-291.7 kN.m c) 311.6 kN.m d)-264.6 kN.m e) 354.2 kN.m 0-242.51 31 What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m c) 14.6 kN.m d)-272.1 kN.m e) 174.1 kN.m f-315.3 ka 41 What is the resultant moment of the five forces acting on the rod about point D? a)-117.8 kN.m b) 82.7 kN.m c) 121.9 kN.m d)-259.9 kN.m 51 What is the moment of the force F2 about point E? Activa
Z. F1 = 500 N O A) -900 i + 200 j + 800 k N 4 m B) 200 i - 900 j + 800 k N F3 C) -200 i+900 j -800 k N 3 m O D) -300 i+ 800 j-900 k N 2 m F2 = 400 N O E) -800 i+ 200 j-900 k N F; = {-200i + 500j – 300k} N. What is the resultant force in vector form?
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F1=3 kN F2=11 kN -60 F3=2 kN A B. 2 m 7 m F4 - 20 kN E a30 FS-2 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 10.8 kN.m e) 14.6 kN.m e) 4.1 kN.m 9 21.3 kN.m b) 12.7 kN.m d) 5.9 kN.m 21 What is the resultant moment of the five forces acting on the rod about point C? a) 8.8 kN.m b) 2.7 kN.m e) 31.6 kN.m d) 8.9 kN.m ) 11.1 kN.m 0 24.2 kN.m 31 What is the moment of the force F1 about point E? a) - 25.7 kN.m ) - 14.6 kN.m d) - 39.1 kN.m e) - 44.1 kN.m b) -11.1 kN.m 0-15.3 kN.m 4] What is the moment of the force F2 about point D? a) 17.8 kN.m b) 8.7 kN.m e) 10.6 kN.m d) 12.9 kN.m e) 27.1 kN.m ) 30.1 kN.m 5] What is the moment of the force F5 about point A? ) - 4.6 kN.m a) - 1.7 kN.m b) -18.1 kN.m d) - 3.1 kN.m e) - 11.1 kN.m 0-21.3 KN.m
15 - A) -900 i + 3500 j + 3200 k NmB) -900 i - 3200 j + 3500 k NmC) -3200 i + 3500 j + 900 k NmD) 3500 i + 700 j + 3200 k NmE) -3200 i + 900 j + 3500 k Nm
A=Ai+Aj |4=√√A,²+A₂² Problem 1 (a). b) c) d) Ya 30° 60° F, 20 kN F, X 16 KN Three forces, F1, F2, and F3, act on a bracket. The magnitude of F3 is 10 kN. If the resultant force, R acts along the x- direction (horizontal), determine the direction angles of the Cartesian force vector, F3. Determine the magnitude of the resultant force, R. A₁ = 4 cos a A, = 4|cos B cos² a + cos² B=1 Determine the FORCE vector, F3 FORCE vector, F1 =__ FORCE vector, F2 = Determine the direction angles, a and ß of the force, F3 [HINT: find 3 first] FORCE vector, F3=_ Determine resultant force vector, R FORCE vector, R= B= α= kN kN O O kN KN
1-What is the magnitude of the resultant force when (F1= 60j + 80k) N and (F2= 50i – 100j + 100k) N? y a) 188 N b) 120 N c) 181 N d) 191 N F= 60j + 80k N F 50i-100j + 100k N
34 - three-dimensional F1 = 39i + 79j + 246k F2= 135i - 253j + 82k for vectors F1 + F2 =? do the collection.A) 174i - 174j + 328kB) 106i - 17j + 112kC) 154i - 49j + 160kD) 666i - 593j - 43kE) 121i + 62j + 117k
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O A) -900 i- 3200 j+3500 k Nm F1 = 500 N O B) 3500 i+700 j+ 3200 k Nm 4 m F3 O C) -3200i+900 j+3500 k Nm O D) -900 i+3500 j+ 3200k Nm 3 m O E) -3200 i+3500 j+ 900 k Nm 2 m F2 = 400 N F3 = {-200i + 500j – 300k} N. What is the total moment of three forces about point O?
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