5)7(motors200001000000BOODD600004000020000A projectile has an initial velocity of 2000 m/s at an angle of 45° above the horizontal.The projectile experiences an acceleration due to gravity and aerodynamic drag:0Determine the trajectory followed by the package and compare it with thetrajectory with no aerodynamic drag.WITH DRAG50000100000a = -9.81ĵ-0.0273 V²150000With Drag200000250000x (meters)-Series2300000V mV S²WITHOUT DRAG360000400000450000

Answered: Image /qna-images/answer/facfa0e7-6231-4b77-819a-478735b3c4e7.jpg

A projectile has an initial velocity of 2000 m/s at an angle of 45° above the horizontal. The projectile experiences an acceleration due to gravity and aerodynamic drag: V m a = -9.81ĵ-0.0273 V². V s2 Determine the trajectory followed by the package and compare it with the trajectory with no aerodynamic drag.

A projectile has an initial velocity of 2000 m/s at an angle of 45° above the horizontal. The projectile experiences an acceleration due to gravity and aerodynamic drag: V m a = -9.81ĵ-0.0273 V². V s2 Determine the trajectory followed by the package and compare it with the trajectory with no aerodynamic drag.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A football player throws the ball with the initial conditions as shown in the figure. Calculate the radius of curvature and the rate of change of velocity dv/dt at t=1s and t=2s. t=0 is the moment the ball leaves the player's hand.
At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be represented by two components. One component is the gravitational acceleration g = 9.56 m/s2 at this altitude. The second component equals 11.25 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of 47.9 km and has reduced its orbital velocity of 28300 km/h to 14750 km/h in the direction = 1.88°. For this instant, calculate the radius of curvature of the path and the rate i at which the speed is changing. Answers: p= i = i FU km m/s²
i need the answer quickly
At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be represented by two components. One component is the gravitational acceleration g = 9.67 m/s² at this altitude. The second component equals 10.66 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of 49.6 km and has reduced its orbital velocity of 28300 km/h to 16160 km/h in the direction = 1.23°. For this instant, calculate the radius of curvature of the path and the rate i at which the speed is changing. Answers: p= i = i i km m/s²
Your answer is partially correct. A train at a constant 53.0 km/h moves east for 49.0 min, then in a direction 52.0° east of due north for 29.0 min, and then west for 59.0 min. What are the (a) magnitude and (b) angle (relative to east) of its average velocity during this trip?
A particle's displacement is defined as s = 2t3 - 30t2 + 100t -50, where s is in feet and t is in seconds. Plot the displacement, velocity, and acceleration of the first 12 seconds of motion as functions of time. Calculate the time when the velocity is equal to zero. (t1 at v=0) and (t2 at v=0)
At the instant of vertical launch, the rocket expels exhaust at the rate of 115 kg/s with an exhaust velocity of 545 m/s. If the initial vertical acceleration is 7.6 m/s?. a Calculate the total mass of the rocket and fuel in kg at launch. Insert your answer correct up to at least a third decimal place. USA
A projectile is launched with a speed v0 = 50 m/s at angle = 35°. How long does it take to reach the maximum height? y vo x 0 2.55 s 28.68 s O2.92 s O 5.10 s
The ball is kicked from a point as shown in the figure with the initial velocity VA=8 m/s. is the maximum height reached by the ball in meters. 8 m/s 30 O a. 5.2 O b. 0.81 O c. 0.2 O d. 4.2
Car has velocity 11 m/s. It starts braking and the acceleration is known a(v)=-0.03*v^2. What is the velocity of the car 3 seconds after it started braking and how many meters it travel in that 3 seconds?
Dynamics
The force acting on the particle is equal to the rate of change of of the particle. Acceleration Velocity Linear momentum Impulse