At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be represented by two components. One component is the gravitational acceleration g = 9.56 m/s² at this altitude. The second component equals 11.25 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of 47.9 km and has reduced its orbital velocity of 28300 km/h to 14750 km/h in the direction = 1.88°. For this instant, calculate the radius of curvature of the path and the rate i at which the speed is changing. Answers: p= v= i km m/s²

At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be represented by two components. One component is the gravitational acceleration g = 9.56 m/s² at this altitude. The second component equals 11.25 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of 47.9 km and has reduced its orbital velocity of 28300 km/h to 14750 km/h in the direction = 1.88°. For this instant, calculate the radius of curvature of the path and the rate i at which the speed is changing. Answers: p= v= i km m/s²

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.

Question

At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be
represented by two components. One component is the gravitational acceleration g = 9.56 m/s2 at this altitude. The second
component equals 11.25 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of
47.9 km and has reduced its orbital velocity of 28300 km/h to 14750 km/h in the direction = 1.88°. For this instant, calculate the
radius of curvature of the path and the rate i at which the speed is changing.
Answers:
p=
i =
i
FU
km
m/s²

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