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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2.   (4) Calculate the magnitude of the normal force from the ground N=___(N)  (two decimal places).

A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2.   (4) Calculate the magnitude of the normal force from the ground N=___(N)  (two decimal places).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2.

 

(4) Calculate the magnitude of the normal force from the ground N=___(N)  (two decimal places).




 
 
 
 

A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The kinetic friction is μ =0.1. The angle of the force P is 8-30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s² (4) Calculate the magnitude of the normal force from the ground N=____(N) (two decimal places). P
Transcribed Image Text:A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The kinetic friction is μ =0.1. The angle of the force P is 8-30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s² (4) Calculate the magnitude of the normal force from the ground N=____(N) (two decimal places). P
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