A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s2. (2) Calculate the the velocity at 2 seconds v= ___(m/s ) (two decimal places).
A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s2. (2) Calculate the the velocity at 2 seconds v= ___(m/s ) (two decimal places).
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s2.
(2) Calculate the the velocity at 2 seconds v= ___(m/s ) (two decimal places).
![A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The
kinetic friction is μ = 0.1. The angle of the force P is 8=30° with respect to the horizontal
direction. The acceleration due to gravity is g=9.81 m/s²
(2) Calculate the the velocity at 2 seconds v=___(m/s) (two decimal places).
P](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72d490d0-ea92-4353-8b1a-fc4847a9a9b3%2F6d16e0d7-a17a-4560-be9c-4ab5b2bde6b2%2Fc14bpl_processed.png&w=3840&q=75)
Transcribed Image Text:A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The
kinetic friction is μ = 0.1. The angle of the force P is 8=30° with respect to the horizontal
direction. The acceleration due to gravity is g=9.81 m/s²
(2) Calculate the the velocity at 2 seconds v=___(m/s) (two decimal places).
P
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