A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s2. (1) Select the motion of equation along the horizontal direction, where F is the friction force, N is the normal force from the ground, and a is the acceleration.___________ A.Pcos30°-F=0 B.Psin30°-F=ma C.Psin30°-F=0 D.Pcos30°-F=ma A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. Thekinetic friction is 4 -0.1. The angle of the force P is 0-30° with respect to the horizontaldirection. The acceleration due to gravity is g=9.81 m/s²(1) Select the motion of equation along the horizontal direction, where F is the frictionforce, N is the normal force from the ground, and a is the acceleration.O A. Pcos30°-F-0O B. Psin30°-F=maO C. Psin30°-F-0O D. Pcos30°-F=maP

Given:m=100 KgP=200 Nμk=0.1θ=30°g=9.81m/s2

Answered: A 100-kg box is towed to move…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μ_k =0.1. The angle of the force P is θ=30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s².

(1) Select the motion of equation along the horizontal direction, where F is the friction force, N is the normal force from the ground, and a is the acceleration.___________

A.

Pcos30°-F=0

B.

Psin30°-F=ma

C.

Psin30°-F=0

D.

Pcos30°-F=ma

A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The
kinetic friction is 4 -0.1. The angle of the force P is 0-30° with respect to the horizontal
direction. The acceleration due to gravity is g=9.81 m/s²
(1) Select the motion of equation along the horizontal direction, where F is the friction
force, N is the normal force from the ground, and a is the acceleration.
O A. Pcos30°-F-0
O B. Psin30°-F=ma
O C. Psin30°-F-0
O D. Pcos30°-F=ma
P

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