At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be represented by two components. One component is the gravitational acceleration g = 9.67 m/s² at this altitude. The second component equals 10.66 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of 49.6 km and has reduced its orbital velocity of 28300 km/h to 16160 km/h in the direction = 1.23°. For this instant, calculate the radius of curvature of the path and the rate i at which the speed is changing. Answers: p= i = i i km m/s²

At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be represented by two components. One component is the gravitational acceleration g = 9.67 m/s² at this altitude. The second component equals 10.66 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of 49.6 km and has reduced its orbital velocity of 28300 km/h to 16160 km/h in the direction = 1.23°. For this instant, calculate the radius of curvature of the path and the rate i at which the speed is changing. Answers: p= i = i i km m/s²

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Conservation of Energy

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Question

At a certain point in the reentry of the space shuttle into the earth's atmosphere, the total acceleration of the shuttle may be
represented by two components. One component is the gravitational acceleration g = 9.67 m/s² at this altitude. The second
component equals 10.66 m/s² due to atmospheric resistance and is directed opposite to the velocity. The shuttle is at an altitude of
49.6 km and has reduced its orbital velocity of 28300 km/h to 16160 km/h in the direction = 1.23°. For this instant, calculate the
radius of curvature of the path and the rate i at which the speed is changing.
Answers:
p=
i =
i
i
km
m/s²

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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s2. (5) Calculate the magnitude of the the friction force F= ___(N) (two decimal places).
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