A jogger with mass m = 55 kg uses energy at a rate of P = 802 W when she jogs on horizontal ground at a constant speed of s = 3.5 m/s. The efficiency of her “human engine” however, is e = 0.27. (In other words, the power used for locomotion is e = 0.27 times the total power.) Q) Write an expression for the rate of energy expenditure whenshe jogs at the same constant speed up a slope of 4.99 degrees. Assume whatever frictional or drag forces are the same in each case. Your answer should be in terms of the symbols given in the problem statement and g(9.80 m/s^2)
A jogger with mass m = 55 kg uses energy at a rate of P = 802 W when she jogs on horizontal ground at a constant speed of s = 3.5 m/s. The efficiency of her “human engine” however, is e = 0.27. (In other words, the power used for locomotion is e = 0.27 times the total power.) Q) Write an expression for the rate of energy expenditure whenshe jogs at the same constant speed up a slope of 4.99 degrees. Assume whatever frictional or drag forces are the same in each case. Your answer should be in terms of the symbols given in the problem statement and g(9.80 m/s^2)
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A jogger with mass m = 55 kg uses energy at a rate of P = 802 W when she jogs on horizontal ground at a constant speed of s = 3.5 m/s. The efficiency of her “human engine” however, is e = 0.27. (In other words, the power used for locomotion is e = 0.27 times the total power.)
Q) Write an expression for the rate of energy expenditure whenshe jogs at the same constant speed up a slope of 4.99 degrees. Assume whatever frictional or drag forces are the same in each case. Your answer should be in terms of the symbols given in the problem statement and g(9.80 m/s^2)
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