The position of a particle is given by s = 0.23t³ -0.77t² -2.50t + 5.65, where s is in feet and the time t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 12 seconds of motion. After you have the plots, answer the questions as a check on your work. -+s, ft -1 0 1 2 3 Questions: When t = 1.7 sec, V= ft/sec, ft/sec² When t = 9.8 sec, v = ft/sec, ft/sec² The positive time at which the particle changes direction is i i a = i a = sec.
The position of a particle is given by s = 0.23t³ -0.77t² -2.50t + 5.65, where s is in feet and the time t is in seconds. Plot the displacement, velocity, and acceleration as functions of time for the first 12 seconds of motion. After you have the plots, answer the questions as a check on your work. -+s, ft -1 0 1 2 3 Questions: When t = 1.7 sec, V= ft/sec, ft/sec² When t = 9.8 sec, v = ft/sec, ft/sec² The positive time at which the particle changes direction is i i a = i a = sec.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Particle Motion Analysis
#### Problem Statement:
The position of a particle is given by the equation:
\[ s = 0.23t^3 - 0.77t^2 - 2.50t + 5.65 \]
where **s** is the position in feet and **t** is the time in seconds.
#### Task:
1. Plot the displacement (\(s\)), velocity (\(v\)), and acceleration (\(a\)) as functions of time for the first 12 seconds of motion.
2. Answer the following questions based on your plots.
#### Provided Diagram:
- A number line depicting the position \(s\) in feet is given, indicating a range from -1 to +3 feet.
#### Questions:
1. **Evaluate the Velocity and Acceleration:**
- **At \( t = 1.7 \) sec:**
- Velocity \( v = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec
- Acceleration \( a = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec²
- **At \( t = 9.8 \) sec:**
- Velocity \( v = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec
- Acceleration \( a = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec²
2. **Determine the time when the particle changes direction:**
- The positive time at which the particle changes direction is \( \quad \_\_\_\_\_\_\_\_\_ \) sec.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5ccfa63-45b7-473c-bb11-56af9dc664c7%2F83ea2655-b9b7-4655-aba4-d1873609843a%2Fjq0bb0qgv.png&w=3840&q=75)
Transcribed Image Text:### Particle Motion Analysis
#### Problem Statement:
The position of a particle is given by the equation:
\[ s = 0.23t^3 - 0.77t^2 - 2.50t + 5.65 \]
where **s** is the position in feet and **t** is the time in seconds.
#### Task:
1. Plot the displacement (\(s\)), velocity (\(v\)), and acceleration (\(a\)) as functions of time for the first 12 seconds of motion.
2. Answer the following questions based on your plots.
#### Provided Diagram:
- A number line depicting the position \(s\) in feet is given, indicating a range from -1 to +3 feet.
#### Questions:
1. **Evaluate the Velocity and Acceleration:**
- **At \( t = 1.7 \) sec:**
- Velocity \( v = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec
- Acceleration \( a = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec²
- **At \( t = 9.8 \) sec:**
- Velocity \( v = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec
- Acceleration \( a = \quad \_\_\_\_\_\_\_\_\_ \) ft/sec²
2. **Determine the time when the particle changes direction:**
- The positive time at which the particle changes direction is \( \quad \_\_\_\_\_\_\_\_\_ \) sec.
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