Q5 50 Create a divide and conquer algorithm for multiplication you do not need to analyze the runtime though, based on this equation. Let X be an integer with n digits. We divide X into: • XL: First [n/3] digits (approximately one-third of the digits) XR: Last n[n/3] digits (approximately two-thirds of the digits) Similarly, we break Y into: • Y: First [n/3] digits YR: Last n [n/3] digits Representing X and Y XXL 102/3 + XR Y Y 102/3 + YR Multiplying X and Y To multiply X and Y: XXY = (XL 102/3 + XR) × (YL · 102n/3+YR)

Database System Concepts
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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Please solve the following algorithms problem: ( show all work solve asap ) 

Q5
50
Create a divide and conquer algorithm for multiplication you do not need to analyze the
runtime though, based on this equation.
Let X be an integer with n digits. We divide X into:
•
XL: First [n/3] digits (approximately one-third of the digits)
XR: Last n[n/3] digits (approximately two-thirds of the digits)
Similarly, we break Y into:
•
Y: First [n/3] digits
YR: Last n [n/3] digits
Representing X and Y
XXL 102/3 + XR
Y Y 102/3 + YR
Multiplying X and Y
To multiply X and Y:
XXY = (XL 102/3 + XR) × (YL · 102n/3+YR)
Transcribed Image Text:Q5 50 Create a divide and conquer algorithm for multiplication you do not need to analyze the runtime though, based on this equation. Let X be an integer with n digits. We divide X into: • XL: First [n/3] digits (approximately one-third of the digits) XR: Last n[n/3] digits (approximately two-thirds of the digits) Similarly, we break Y into: • Y: First [n/3] digits YR: Last n [n/3] digits Representing X and Y XXL 102/3 + XR Y Y 102/3 + YR Multiplying X and Y To multiply X and Y: XXY = (XL 102/3 + XR) × (YL · 102n/3+YR)
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