Q3: The following figure shows spot levels at 25 m intervals over a small site which is to be made level at 15 m. Calculate the volume of earthwork? 14.6 14.6 2 154 14.7 14:14 14.5 2 14.6 1 ㅍ 15 14.8

Q3: The following figure shows spot levels at 25 m intervals over a small site which is to be made level at 15 m. Calculate the volume of earthwork? 14.6 14.6 2 154 14.7 14:14 14.5 2 14.6 1 ㅍ 15 14.8

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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8. RISB AND FALL camplete the level notes given: below and show the customary arithmetic check. METHOD. Using the rise and fall method, ROD READINGS IFS DIFFERENCE IN ELEV RISE REDUCED LEVEL STA BS FS FALL 1.73 766.45 m BM13 O+00 2.05 +35 1.88 +60 1.75 + B0 I +00 2.39 3.25 +15 2.44 +40 1.86 +90 1.09 2+00 2.15 TP- 1.84 2.63 2+45 О.77 +68 3+00 1.19 1.08 +50 2.52 BM 14 2.J4
P1. Volume Computation using Contour Method The great Lake Buwis was surveyed by Engr. Guanzon. The bathymetric data was used to compute for the area enclosed by each contour line. From the figure below and the computed areas, solve for the ff: Area in km? 10,882.64 8,928.73 8,077.11 6,751.50 5,381.82 4,462.94 3,497.25 A1 A2 A1 A2 АЗ A3 A4 A4 А5 A5 A6 A6 5m A7 A7 * assume A7 is the bottom of the lake 10m 15m 20m 25m 30m 35m (a) Total Volume using Average End Area Method in m3 (b) Total Volume using Prismoidal Method in m3 (c) Difference between total volumes acquired from the two methods
RISE AND FALL LEVELLING Reduce the following reading using rise and fall method. Point BS IS FS Rise Fall RL Corr. Adjusted FINAL Height HEIGHT + BM5 10 1,528 1,354 1546,915 1546,915 1,145 11 0,967 1,025 0,814 0,541 12 13 1,462 14 1,324 0,822 15 1,278 1,541 1,298 0,985 16 BM3 1,458 1550,00 1550,00
3. The boundary of the water surface of a reservoir is shown by irregular outline KLMNOPQR. Soundings were taken on parallel ranges QK, PL, and OM for the purpose of determining the volume of water in the reservoir. The horizontal distances (m) which were measured for locating the ranges and the soundings, and also the depth (m) which were measured where soundings were taken are shown. Calculate the following: a. Areas (sq.m.) of the cross-sections of ranges QK, PL, and OM. Assume that the cross-sectional areas of ranges R and N are negligible or nearly zero. b. Volume (cu.m.) of water between ranges. c. Total volume (cu.m.) of water contained in the reservoir. R 5.275 Q 2658 t612 -5.591- -7.874- -4.754- 2.150 6.496 -6.725 -3.052- -7.151- -6.499- -5.498- 2,55N 1.076 2.077 3.754 2.636 3.428 8.390 -5.251- +3.676 -5.994 -5.497- -6.031- !! 0.873 0.902 1.714 M 2.702 9. 106 N
N Rod ++ 50 1+50 1+75 2.6 Complete the set of differential leveling notes in Table 2-5, and perform the arithmetic 2.5 Prepare a set of profile leveling notes for the survey in Figure 2-34. In addition to comput- ing all elevations, show the arithmetic check and the resulting error in closure. check. 5.11 4.66 3.98 1.20 1.80 TP 2 4.42 4.30 2.01 Known Elevation is 402.78 4.72 TP 1 BM 61 Elevation = %3D 396.74 FIGURE 2-34 5-35 ()
kindly asnwer
*refer from the illustration attached* determine: (a) Resolve the attached problem if the vertical distance between contour levels is 2.0m. Which has a larger value of volume? Make a conclusion of your answer. ***COMPLETE SOLUTION; 3 decimal places all answer; with Diagram.
Please answer 15.18
2. A lake 800 m long had soundings taken at right angles to its length on ranges 0, 225, 400, 650, and 800 m (measured from one end of the lake). The calculated cross-sectional area of the different ranges are: Ao = 60 sq. m, A225 = 930 sq m, A400 = 640 sq m, A650 = 750 sq m, and As00 = 120 sq m. Compute the total volume of water in the lake.
FS 2.875 m 4.252 m 5.478 m 6.142 m BS ТР 1 ТР 2 4.325 m 9.542 m 9.631 m 8.133 m BM 1 Elev. = 56.287 m ТР 3 Not to scale BM 2 Given the traverse illustration above, fill up and complete the table below. Make sure to show your solution in solving for HI, Elevation, Correction to be applied, and Corrected Elevation. BS HI FS Elevation Corrected Station (m) (m) (m) (m) Elevation (m) BM1 TP1 BM2 TP3 TP4 BM1 7.258 m 2.841 m