b. The surveyor's first reading was to TBM 41 with reading 5.76, she then took thefollowing readings (see table below) and closed the survey with reading 5.77 to TBM 41.Station12Rod reading 2.21 3.545.714.524.85TP132.585.11412.555.48TP2567814.65 8.26 16.84 11.544.845.42TP36.24TP4921.555.574100.876.31BM BBM ACalculate the elevation of all the points she surveyed and the misclosure in the survey.

First Reading at TBM 41 =5.76 Last Reading at TBM 41 =5.77 Assume the elevation of TBM 41 =100

b. The surveyor's first reading was to TBM 41 with reading 5.76, she then took the following readings (see table below) and closed the survey with reading 5.77 to TBM 41. Station 1 2 Rod reading 2.21 3.54 5.71 4.52 4.85 TP1 6 7 8 9 3 4 5 2.58 12.55 14.65 8.26 16.84 11.54 21.55 5.11 5.48 TP2 4.84 5.42 TP3 6.24 11- TP4 5.57 10 0.87 6.31 BM B BM A Calculate the elevation of all the points she surveyed and the misclosure in the survey.

b. The surveyor's first reading was to TBM 41 with reading 5.76, she then took the following readings (see table below) and closed the survey with reading 5.77 to TBM 41. Station 1 2 Rod reading 2.21 3.54 5.71 4.52 4.85 TP1 6 7 8 9 3 4 5 2.58 12.55 14.65 8.26 16.84 11.54 21.55 5.11 5.48 TP2 4.84 5.42 TP3 6.24 11- TP4 5.57 10 0.87 6.31 BM B BM A Calculate the elevation of all the points she surveyed and the misclosure in the survey.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A distance AB is observed repeatedly using the same equipment and procedure, and the results in…

A: computation of most probable value in 4 and 5 part since most probable length is that length of…

Q: Q: Using a digital laser level instrument, the following staff readings were observed via an open…

A: Here we have given a open loop and we will use rise and fall method to calculate the RL's of each…

Q: 1. The surveying team at UTM can make taping measurements with an error of ±0.03 ft per 100-ft tape…

A: Note:- Hi! Thank you for the question As per the honor code, We’ll answer the first question since…

Q: During the dumpy level test, the observations are as follows: Staff reading station Instrument…

A: Given, The staff reading of A when station at A, a1 = 1.605 The staff reading of B when station at…

Q: A field party is capable of making taping observations with a standard deviation of +/-0.003 m per…

Q: Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a…

A: Using the following formulae: RL+BS=HI HI-(IS/FS)=RL BS-IS=Rise/Fall Previous RL±Rise/Fall=Next RL

Q: 12. Complete the benchmark-leveling field notes shown in Figure B by computing and recording the HI…

A: Objective: To completer the given leveling notes and perform the arithmetic checks. Given: Sta.…

Q: No. 2. Measurment of three horizontal angles; about a point P are: APB = 12°31'50", BPC = 37°29'20",…

Q: a) Determine the true difference in elevation between A and B b) Determine the error in the rod…

Q: 6. A line was measured 5 times with a tape on a windy day with these results: 286.85, 286.96,…

A: Given:- The results of the 5 times line measurement with a tape = 286.85, 286.96, 286.77, 286.80,…

Q: 10. RECIPROCAL LEVELING. Reciprocal leveling between points A and B, 1ocated on opposite banks of a…

Concept explainers

Methods of Surveying

Surveying is the practice to determine the relative three-dimensional positions of various points on the earth’s surface. This is done by computing the vertical and horizontal distances, angles between the points, collecting the observations, and plotting them on a map of any appropriate scale. Accuracy can be achieved by using the latest instruments like a theodolite, tachometer, etc. Leveling is a subdivision of surveying where the objective is to locate the elevation of objects considering a datum level.

Question

b. The surveyor's first reading was to TBM 41 with reading 5.76, she then took the
following readings (see table below) and closed the survey with reading 5.77 to TBM 41.
Station
1
2
Rod reading 2.21 3.54
5.71
4.52
4.85
TP1
3
2.58
5.11
4
12.55
5.48
TP2
5
6
7
8
14.65 8.26 16.84 11.54
4.84
5.42
TP3
6.24
TP4
9
21.55
5.57
4
10
0.87
6.31
BM B
BM A
Calculate the elevation of all the points she surveyed and the misclosure in the survey.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Given Data

VIEW

Step 2: Calculation

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 190.000(fixed) 35 36 37 38 39 35 188.242 186.299 188.251 186.397 190.033 IM 36 09 km DM 35 0.8 km OBM 37 08 km O6 km DM 39 BM 30 0.7 km
Elementary Surveying
N Rod ++ 50 1+50 1+75 2.6 Complete the set of differential leveling notes in Table 2-5, and perform the arithmetic 2.5 Prepare a set of profile leveling notes for the survey in Figure 2-34. In addition to comput- ing all elevations, show the arithmetic check and the resulting error in closure. check. 5.11 4.66 3.98 1.20 1.80 TP 2 4.42 4.30 2.01 Known Elevation is 402.78 4.72 TP 1 BM 61 Elevation = %3D 396.74 FIGURE 2-34 5-35 ()
A line was measured three times and yield the following results: 856.42, 856.69 and 856.12 m. Determine the probable error of the mean.
wh
P Give suitable examples as you discuss how errors in surveying activities are classified. The three angles of a triangle were measured using a triangulation scheme, and their mean values were reported as 50° 48′ 18′′, 64° 2036", and 64° 5100".Each of these means has a standard deviation of 4 according to analysis of each set.The angles were measured again at a later time under better lighting, resulting in mean values of 64° 20′ 39", 64° 50' 58", and 50° 48' 20" prime prime Each value's standard deviation was 2 n. Determine the most probable values of the angles
SITUATION 3. a) The base and altitude of a triangle lot were measured to have certain probable errors of 314.60 0.16 and 92.60 = 0.14, compute the probable error of the resulting computation. (3- b) The following sides of a rectangle and its probable errors are 120.40 0.04 and 360.50 ± 0.08 respectively. Compute the probable errors of the sum of the sides (perimeter) of rectangle. (3r c) The probable error of the mean of 6 observation is 0.043 and the most probable value of the measurement is 860 m compute the relative precision. C
Surveying Question: A differential leveling circuit starts at benchmark Concrete Benchmark (Elevation=232.051m) goes out to an unknown benchmark and then continues to a known control point (Elevation=227.975m). Two turning points are used with the measurements included in the attached table. Determine the elevation of the unknown benchmark Determine the order and class of the survey. For First order Class 1: Allowable Error= +/- 4(K)1/2 Range of Constant= m less than/equal to 4 For First Order Class 2: Allowable error= +/- 5(K)1/2 Range of constant= m greater than/equal to 4, and m less than equal to 5 (between 4 and 5) For Second Order Class 1: Allowable error = +/- 6(K)1/2 Range of Constant = m greater than/equal to 5, and m less than equal to 6 (between 5 and 6) For Second Order Class 2: Allowable error = +/- 8(K)1/2 Range of Constant = m greater than/equal to 6, and m less than equal to 8 (between 6 and 8) For Third Order, Any Class: Allowable Error = +/-12(K)1/2 Range…