in c++ please Q2: In remove() member function, add tow debug points at remove_10); and remove_2();calls(line) as seen in the picture, then call the function to remove 10, 48, 30,26.Then run the debug mode, now for each remove node, which functions was calles (remove_1 orremove_2)Answers:For 10:For 48:For 30:For 26:For 12:Explain why for each step:Attach the screenshots for each removal.796if (node->left797== nullptr node->rightremove_1(node, prev);==nullptr)798else799remove_2(node);

Step-by-Step Explanation of the remove() FunctionThe provided code snippet shows that, in the…

Answered: Q2: In remove() member function, add…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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typedef struct node_t node_t; struct node_t { }; int32_t value; node_t* next; node_t* insert (node_t* list, int32_t v, int32_t* flag); 3) As you may have noticed from MT1, Howie is lazy. He wants you to write the interface for the following implementation of function copy_to_linked_list. He really appreciates your help! /* copy_to_linked_list int32_t copy_to_linked_list (int32_t a[], int32_t size, node_t** list_p) { int32_t flag, i; for (i = 0; i < size; ++i) { *list_p = insert (*list_p, a[i], &flag); if (-1== flag) return -1; } return 0;
Write a function called rem_duplicate that takes a tuple in the parameter and return a tuple removing all the duplicate values. Then print the returned tuple in the function call. Hints: Unlike lists, tuples are immutable so, the tuple taken as an argument cannot be modified. But list can be modified and lastly for returning the result use type conversion. You need to use membership operators (in, not in) for preventing adding any duplicates values. Example1: Function Call: rem_duplicate((1,1,1,2,3,4,5,6,6,6,6,4,0,0,0)) Output: (1, 2, 3, 4, 5, 6, 0) %3D %3D %3D %3D %3D %3D %3D %3D II %3D %3D %3D %3D %3D %3D %3D %3D %3D %3D %3D %3D %3D %3D %3D II %3D %3D %3D %3D I3D %3D I3D %3D %3D
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Question 1: Add a member function to LinkedList called insertAfter. The function should insert a new node after another Node that contains a target value. Your function should do nothing if the target value is not in the list. Question 2: Write a function that takes these parameters Node* list1 Node* list2 Concatenate list1 onto list 2 so that they form one long linked list. Question 3: Create a circular Linked list. It has node 1, 2, 3, 4, 5. And the last node points to node 1.
Please help to fill the blank statements to complete the Append function of Doubly linked list, which has Head node(Dummy head node). typedef struct Node { int data; struct Node *next; struct Node *prev; } Node; void append(int x) { // current is pointing to first element, we iterate until we find the end // Head is a Global variable, which pointer to the Head node with Empty data of Doubly linked list Node* current = Head; while(current->next != current = current->next; ) { } // create a new Node and append the item into the end of list current->next = (Node *)malloc(sizeof(Node)); current->next->data = x; = Head; = current; = current->next;
Write a function, to be included in an unsorted linked list class, called replace_item, that will receive two parameters, one called olditem, the other called newitem. The function will replace all occurrences of olditem with newitem ( if olditem exists !! ) and it will return the number of replacements done.
Write a function called rem_duplicate that takes a tuple in the parameter and return a tuple removing all the duplicate values. Then print the returned tuple in the function call. ====== ====== Hints: Unlike lists, tuples are immutable so, the tuple taken as an argument cannot be modified. But list can be modified and lastly for returning the result use type conversion. You need to use membership operators (in, not in) for preventing adding any duplicates values. ======= ========= Example1: Function Call: rem_duplicate(1,1,1,2,3,4,5,6,6,6,6,4,0,0,0)) Output: (1, 2, 3, 4, 5, 6, 0) Example2: Function Call: rem_duplicate(("Hi", 1, 2, 3, 3, "Hi",'a', 'a', [1,2])) Output: ('Hi', 1, 2, 3, 'a', [1, 2])
Max Absolute In List Function Lab Description Implement function max_abs_val(lst), which returns the maximum absolutevalue of the elements in list.For example, given a list lst: [-19, -3, 20, -1, 0, -25], the functionshould return 25. The name of the method should be max_abs_val and the method should take one parameter which is the list of values to test. Here is an example call to the function print(max_abs_val([-19, -3, 20, -1, 0, -25])) File Name maxabsinlst.py Score There are three tests each worth 2 points Note: You do not need any other code including the main method or any print statements. ONLY the max_abs_val method is required. Otherwise, the autograder will fail and be unable to grade your code. (I.e., do not include the above example in your code.) The above example should be used be test your code but deleted or comment out upon submission. PYTHON LAB
Please implement this function: void swap(int pos1, int pos2) {}. There's an answer from the previous teacher but he added '' node** hRef " in the function (see below) please correct without the href. For LinkedList, to maintain integrity of data in the structure, you are not to swap directly the element, nor remove a node. Instead, you are to only change the nodes' next pointers. PLEASE CORRECT THIS ONE void swap(node** hRef, int pos1, int pos2) { if (pos1 == pos2) return; node *prevNode1 = NULL; node* currNode1 = *hRef; while (currNode1 && currNode1->index != pos1) { prevNode1 = currNode1; currNode1 = currNode1->next; } node *prevNode2 = NULL; node *currNode2 = *hRef; while (currNode2 && currNode2->index != pos2) { prevNode2 = currNode2; currNode2 = currNode2->next; } if (currNode1 == NULL || currNode2 == NULL) return; if (prevNode1 != NULL) prevNode1->next =…
Q1
This is hard help please its from my study guide in C++ LEVEL 2
Implement the following Racket functions: Reflexive? Input: a list of pairs, L and a list S. Interpreting L as a binary relation over the set S, Reflexive? returns #t if L is a reflexive relation over the set S and #f otherwise. Examples: (display "Reflexive?\n") (Reflexive? '((a a) (b b) (c c)) '(a b c)) ---> #t (Reflexive? '((a a) (b b)) '(a b c)) ---> #f (Reflexive? '((a a) (a s) (b b) (c c)) '(a b c)) ---> #f (Reflexive? '() '()) ---> #t You must use recursion, and not iteration. You may not use side-effects (e.g. set!).

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