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Let be a (non-empty) alphabet and let w € Σ* be a string. We say that x = Σ* is a prefix of the string w if there exists a string u = Σ* such that w = xu. Consider the following language L= {w = {a,b}*|for every prefix x ofwn(x) > na(x)} Prove that L is a context-free language. Your proof should rely on mathematical induction.

Let be a (non-empty) alphabet and let w € Σ* be a string. We say that x = Σ* is a prefix of the string w if there exists a string u = Σ* such that w = xu. Consider the following language L= {w = {a,b}*|for every prefix x ofwn(x) > na(x)} Prove that L is a context-free language. Your proof should rely on mathematical induction.

LINUX+ AND LPIC-1 GDE.TO LINUX CERTIF.
LINUX+ AND LPIC-1 GDE.TO LINUX CERTIF.
5th Edition
ISBN:9781337569798
Author:ECKERT
Publisher:ECKERT
Chapter7: Working With The Bash Shell
Section: Chapter Questions
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Let be a (non-empty) alphabet and let w € Σ* be a string. We say that x = Σ* is a prefix of the string w if there exists a string u = Σ* such that w = xu. Consider the following language L= {w = {a,b}*|for every prefix x ofwn(x) > na(x)} Prove that L is a context-free language. Your proof should rely on mathematical induction.
Transcribed Image Text:Let be a (non-empty) alphabet and let w € Σ* be a string. We say that x = Σ* is a prefix of the string w if there exists a string u = Σ* such that w = xu. Consider the following language L= {w = {a,b}*|for every prefix x ofwn(x) > na(x)} Prove that L is a context-free language. Your proof should rely on mathematical induction.
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