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Problem What is the average CPI of this program? We have the computer from the previous problem with the following specs CPI for each instruction class CPI of A B C CPI 1 2 3 We have the program where the instructions distributed the following way CPI for each instruction class Portion of A B C 50% 35% 15% Lets assume X instructions in the program otes #_cycles = (X instr *0.5) * 1 cycle/instr + (X instr * 0.35)*2 cycle/instr + (X instr * 0.15)*3 cycle/instr = x*0.5 cycle + X*0.7 cycle + X*0.45 cycle = X*1.65 cycle Aver CPIX*1.65 cycles / X instr = 1.65 cycle/instr I

Problem What is the average CPI of this program? We have the computer from the previous problem with the following specs CPI for each instruction class CPI of A B C CPI 1 2 3 We have the program where the instructions distributed the following way CPI for each instruction class Portion of A B C 50% 35% 15% Lets assume X instructions in the program otes #_cycles = (X instr *0.5) * 1 cycle/instr + (X instr * 0.35)*2 cycle/instr + (X instr * 0.15)*3 cycle/instr = x*0.5 cycle + X*0.7 cycle + X*0.45 cycle = X*1.65 cycle Aver CPIX*1.65 cycles / X instr = 1.65 cycle/instr I

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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so over here the average cpi is already solved but 

How fast (in seconds) will the program execute? please show using measurement units in the computation please. 

Problem What is the average CPI of this program? We have the computer from the previous problem with the following specs CPI for each instruction class CPI of A B C CPI 1 2 3 We have the program where the instructions distributed the following way CPI for each instruction class Portion of A B C 50% 35% 15% Lets assume X instructions in the program otes #_cycles = (X instr *0.5) * 1 cycle/instr + (X instr * 0.35)*2 cycle/instr + (X instr * 0.15)*3 cycle/instr = x*0.5 cycle + X*0.7 cycle + X*0.45 cycle = X*1.65 cycle Aver CPIX*1.65 cycles / X instr = 1.65 cycle/instr I
Transcribed Image Text:Problem What is the average CPI of this program? We have the computer from the previous problem with the following specs CPI for each instruction class CPI of A B C CPI 1 2 3 We have the program where the instructions distributed the following way CPI for each instruction class Portion of A B C 50% 35% 15% Lets assume X instructions in the program otes #_cycles = (X instr *0.5) * 1 cycle/instr + (X instr * 0.35)*2 cycle/instr + (X instr * 0.15)*3 cycle/instr = x*0.5 cycle + X*0.7 cycle + X*0.45 cycle = X*1.65 cycle Aver CPIX*1.65 cycles / X instr = 1.65 cycle/instr I
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