The position as a function of time (x(t), y(t))of a projectile fired with a speed of vo at anangle a is given byx(t) = v₁cosα ty(t) = vo sina.t-12812Ꮎ1whereg = 9.81 m/s². The polar coordinates ofthe projectile at time t are (r(t), 0(t)), wherer(t) = √x(t)²+y(t)² and tane = y(1) Consider the case where vox(t)and 0=70°. Determine r(t) and 0(t) for t = 1, 6, 11,31s.=162 m/s

Other values can be computed by changing the t in x(t) and…

Answered: The position as a function of time…

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter1: Fundamentals Of C++ Programming

Section: Chapter Questions

Problem 2PP: (Conversion) An object’s polar moment of inertia, J, represents its resistance to twisting. For a...

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A simple pendulum of length L, has a maximum angular displacement e_max. At one point in its motion, its kinetic energy is K = 3 J and its potential energy is U = 4.2 J. When the pendulum's angular velocity is one-fourth its maximum value (0' = %3D O'_max/4), then its kinetic energy is:
(Conversion) An object’s polar moment of inertia, J, represents its resistance to twisting. For a cylinder, this moment of inertia is given by this formula: J=mr2/2+m( l 2 +3r 2 )/12misthecylindersmass( kg).listhecylinderslength(m).risthecylindersradius(m). Using this formula, determine the units for the cylinder’s polar moment of inertia.
Suppose that a parachutist with linear drag (m=50 kg, c=12.5kg/s) jumps from an airplane flying at an altitude of a kilometer with a horizontal velocity of 220 m/s relative to the ground. a) Write a system of four differential equations for x,y,vx=dx/dt and vy=dy/dt. b) If theinitial horizontal position is defined as x=0, use Euler’s methods with t=0.4 s to compute the jumper’s position over the first 40 s. c) Develop plots of y versus t and y versus x. Use the plot to graphically estimate when and where the jumper would hit the ground if the chute failed to open.
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2. calculates the trajectory r(t) and stores the coordinates for time steps At as a nested list trajectory that contains [[xe, ye, ze], [x1, y1, z1], [x2, y2, z2], ...]. Start from time t = 0 and use a time step At = 0.01; the last data point in the trajectory should be the time when the oscillator "hits the ground", i.e., when z(t) ≤ 0; 3. stores the time for hitting the ground (i.e., the first time t when z(t) ≤ 0) in the variable t_contact and the corresponding positions in the variables x_contact, y_contact, and z_contact. Print t_contact = 1.430 X_contact = 0.755 y contact = -0.380 z_contact = (Output floating point numbers with 3 decimals using format (), e.g., "t_contact = {:.3f}" .format(t_contact).) The partial example output above is for ze = 10. 4. calculates the average x- and y-coordinates 1 y = Yi N where the x, y, are the x(t), y(t) in the trajectory and N is the number of data points that you calculated. Store the result as a list in the variable center = [x_avg, y_avg]…
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