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- Draw a seven-segment display, show the number highlighted in figure 1 (d3 -d0 are the input, a -g are the outputs). III. Simulation Wavetorm Editor - Cers/Ahmad Fainuz/Desanop/DLD Lab Practice/bedseg - beaeg - bcaseg 2018o03121936sim.vwwt Ee ep Ea w smutation search altera.com Haster Time Bar: ops Pointer: s29 us Start End iterval 529 us o ps 0 ps २ 2.56 us S12 us 75 us 10.24 us 12 s 15.36 us 172 us value at Name Ops do Figure 1Ministry of Manpower Directorate General of Technological Education Salalah College of Technology Zlectrical Inginearina Problem - 8 Refer to the circuit below and -25V C2 N. compute the following: i) Total capacitance ii) Voltage across C, iii)Charge across C, iv)Voltage across C5 5 uF C1 5 uF 5 uF C4 5 uF C6 5 uF -16-65V. C5 5 uF (Take V, as 25V) 8-35V VT 25VDraw the phasor diagram. Find magnitudes and positions of all the quantities. Please show complete solution and round off answers up to the 3rd decimal place. Thank you!
- Please disregard the question on the picture. Here's the right question, at what frequency will the value of the impedance be twice that at 25Hz (refer to the given in question #20).Q/Exprees the de cinaluunber (83)(-85)2 see complenust)Find the theoretical values and answer the questions. please answear about all this questions.
- Application: Construct the circuit in figure. R= 2,2KN, L = 1 mH, and C= 10 nF. L Necesssary Formulae: 1 Xc 2.π.f.C X.-2. π.f. L By using the formulea perform the calculations of Xc and XL then fill the table. f (Hz) Xc XL 50000 60000 70000 80000 90000 100000 110000 120000 130000 140000a. The following 40Ω capacitive reactance and 60Ω inductive reactance are in series with a 30Ω resistor in a circuit. The applied voltage is 80mV. Find the total impedance and the power factor of the circuit. Draw the circuit and find the real power that is going through the circuit. c. A signal generator generated a signal according to the function below. Calculate the strength of the signal: g(t) = cos2t – sint 0 ≤ t ≤ π! plz solve it within 30-40 mins I'll give you multiple upvote
- j32 -j6 2 4Ω ww 62 Vo I V /0° V a三 E100 j8 Q I2 E j4 2 For the circuit shown, if V-276, the value of V. in V is O A. -8.998+j3.486 O B. 17.024-j27.294 O C.-53.986+j20.921 O D. 68.095-j109.174 O E. NoneThe figure below shows with two batteries and three resistors. The potential difference across the batteries and the resistance of each resistor is given in the figure. 12.0V 2.00 www 46 8.40 V www 4.000 5.640 (a) What is the current (in A) in the 2.000 resistor? (Enter the magnitude.) 1.480 X Use Kirchhoff's junction and loop rules to find equations to solve for the unknown currents in the branches of the circuit. You will need one junction equation and two loop equations to get three equations and three unknowns. Be careful of sign rules in your equations. A (b) What is the potential difference (in V) between points a and b, that is, AV-V₂-V₂? 2978 x Remember that V-V, refers to the potential at the final point (point b) minus the potential at the initial point (point a). Can you choose a path in the circuit from a to b that uses the current found in part (a)? Be careful of sign rules when finding potential differences along this path. VPlease Solve this question ASAP. Thanks