PROBLEMS8.1. For the following linear time-invariant continuous-time systems, determine if the system isstable, marginally stable, or unstable:(a) H(s)(b) H(s)(c) H(s)===(d) H(s)=S-4s² + 7s+3S+35² + 32s +3s² + 2s -12353- 2s + 6s3+s²+s+1

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Answered: PROBLEMS 8.1. For the following linear…

Introductory Circuit Analysis (13th Edition)

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Publisher:Robert L. Boylestad

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Fast pls solve this question correctly in 5 min pls I will give u like for sure Sini Please provide answers in this format:
A series RC circuit is driven by a voltage source step function. The voltage values across the capacitor begins to rise as a function of time as follows: T( time in seconds) VC voltage across capacitor 10 20 30 40 50 60 70 2.922 4.776 5.954 6.701 7.175 7.476 7.669 Determine which fit is best: linear, power, or exponential for VC vs time (show plots) Plot the raw data and best fitted line from the models above. Find the equation for the best-fit model
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FIRST-ORDER CIRCUIT ANALYSIS (SECTS. 7-1 TO 7-4) Given a first-order RC or RL circuit: (a) Find the circuit differential equation, the circuit time con- stant, and the initial conditions (if not given). (b) Find the zero-input response. (c) Find the complete response for step function, exponential, and sinusoidal inputs. See Examples 7-1 to 7-7, 7-9 to 7-11, 7-15, and 7-16 and Exercises 7-1 to 7-7, 7-9 to 7-13, 7-15, and 7-17 to 7-21. 7-1 Find the function i(t) that satisfies the following differential equation and the initial condition: 1000 di(r) dt + 50ki(t) = 0, i(0) = 50 mA
Charging Capacitor: For a charging capacitor the Kirchoff's Loop Rule gives R E – IR C ww C In this case the current is entering the positive plate so I = dQ/dt = CdAVc/dt and we get dVc E – RC - Vc = 0 dt The solution to the differential equation is V.(t) = E (1 – e-t/(RC)) (charging capacitor) Notice that V.(0) = 0 and V.(0) = E as we expect for a charging capacitor. 5. You can easily find the time constant if you are given a graph of voltage across a charging capacitor as a function of time. Whent = RC, the voltage across the capacitor is V.(t = RC) = E(1 – e-1) × 0.63 E. Therefore the time constant is just how long it takes for AV(t) to reach 63% of the EMF. The graph shows the voltage across a charging capacitor as a function of time. The resistance of the circuit is 7.5 kN. а. Determine the capacitance of the capacitor. 10 8 60 40 time (ms) 20 80 100 b. What is the current at t = 10 ms? Hint: the easiest way to do this is to use the loop rule. (volts) 4.
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PROBLEMS 8.1. For the following linear time-invariant continuous-time systems, determine if the system is stable, marginally stable, or unstable: (a) H(s) (b) H(s) (c) H(s) = = = (d) H(s) = S-4 s² + 7s+3 S+3 5² + 3 2s +3 s² + 2s -12 353 - 2s + 6 s3+s²+s+1