For the circuit below, find the power factor combination (hint: find the total complex power S=S1+ S2), and then find the value of the capacitance that will give a power factor of 0.95when connected to the load. Assume that VRMS = 120 V, 60 Hz. Load 1 20kW pf = 0.7 lagging Load 2 50 kW 120 pf=0.9 lagging
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- The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2VmaxAn industrial load consisting of a bank of induction motors consumes 50 kW at a power factor of 0.8 lagging from a 220-V,60-Hz, single-phase source. By placing a bank of capacitors in parallel with the load, the resultant power factor is to be raised to 0.95 lagging. Find the net capacitance of the capacitor bank in F that is required.An impedance load consisting of 12 ohms resistance and 16 ohms inductance reactance is connected across a 50 Hz, 100 V source. Find the capacitance of the condenser which may be paralleled with this load to bring the power factor to 0.80 leading.
- A load is rated at 440V(rms), 7.5A(rms) and 3.3KW when connected to a 50HZ source. Find the load impedance.Shown in the figure below is an "RC" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 11.58 Volts and is running at a frequency of f = 1.326e+04 Hz. resistor has a resistance of R = 3750 2 and the capacitor has an capacitance of C = 3.17e-09 Farads. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit tot = Determine the numerical value of Ztot = Determine the numerical value of Pztot= Determine the current through the circuit: • I(PEAK) = • I(RMS) = Determine the voltage across the resistor: Amps Amps S2 C degrees5. Two ac sources feed a common variable resistive load as shown in figure. Under the maximum power transfer condition, the power absorbed by the load resistance RL is? 11020° 602 w 18.0 m 652 802 Mm 9020°
- If, in one (360 degrees), all of the instantaneous power falls under positive loops (no negativeloops), the load must be:a. A resistorb. An inductor or capacitorExplain:d. 565.685 V If a Load absorbs 20 kVA at a leading power factor of 0.6. Then the complex power is: Select one: O a. 12000 - j16000 VA O b.-12000 + j16000 VA O c. 12000 + j16000 VA O d. None of these Given the circuit below and the associated set of voltages and currents, the reactive Power developed by im voltage source is FENG300 MINTERM. Determine the capacitance value that, when placed in parallel with this load, would produce a unity power factor. Assume that the source is 230 V at 60 Hz. The Q shown is a positive Inductive reactive power, which would have to be “offset” by the same value of Reactive Capacitance Power.
- 2.14 The current waveforms of la capocitov are avesage peak cursend *atings of 1, =500 A of shown in Fiquse Determine square (rms), and capacitor. Assume, The root mean half sine -wave t = loo us -300 AS t3 Soo Ns f, -250HZ T2 200Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…A 220 Ω resistor is in series with an 80 mH inductor. The AC source is 48 at 1 kHz. The power factor is ________. Hint: Draw the circuit and get Vs and Is