Q4. Find the "?" marked voltage below. Use CVD model for the diode just like Q3. 5V 2 Kn=1mA/v² 3.5 V V₁ = 0.2V Io↓ % = ? 1k52

Diode circuitsFor each circuit below, use the diode approximation with forward dropVF= 0.7 V to find the output voltage. No current flows to the output.

Determine which diodes are forward-biased and which are reverse-biased in the configurations shown in Figure 4. Assuming a 0.7-V drop across each forward-biased diode, determine the output voltage. O+5 V -10 V R DI +s vOK D, -SVOKH D3 +s vOK D4 -5 voK DI -5VOK Dz OVout OVout +5 voK Figure 4.

Draw the corresponding output waveform of the double diode partial limiter below using simplified diode model. Indicate all the necessary voltage levels and use Silicon diodes. 20 VP-P 1KQ M D1 9V D2 4.5V VOUT

Using an ideal diode, design a clamper circuit that result in the desired output waveform as shown in Figure Q7. Show overall analysis to justify the proposed design. 7. Vo Vi Designed Clamper Circuit - 3 V -20 - 43 V - Fiqure Q7 20

solve d-f

Determine the voltage across the diode in the figure below, using the complete diode model with: r'd = 10-? and r'R = 100-M? a. The value of the forward current. (in Amperes) b. The value of the forward voltage.  c. The value of the voltage across the diode.

Consider diode circuit shown below with Vcc=5V and V₂ = 3V. U₁A HH +V₂ ū The peak inverse voltage on the diode is close to V₁ V. A Vo

consider the figure below that shows an approximated reverse recovery turn-off characteristics for a power diode. Show that the following relation can express the total reverse recovery charge, Qrr = 1/2(trr*ts1) di1/dt =1/2(trr*ts21) di2/dt * ip Isl 1s2! -Ir

Draw the changes in Vi and Id of the ideal diode half-wave rectifier circuit in the figure. The frequency of the sine signal here will be taken as 50Hz. (Changes in Vi and Id will be drawn!!!)