Q2) A waste of 600 m*hr flow rate with an ultimate BODZ° = 140 mg/l is to be treated in an activated sludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor the detention time = 6 hrs , sludge age = 10days , under flow SS concentration = 15000mg/1 , decay rate = 0.055 day , yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solid concentration and the solids are 80% volatile.( ky, 20 = 0.24 /day) Find: - 1- MLSS (mg/l) 2- Recirculation ratio Q2) A waste of 600 m/hr flow rate with an ultimate BOD20 = 140 mg/1 is to be treated in an activatedsludge process to yield an effluent of 20mg/l BOD5 and 25mg/ suspended solids. For the reactor thedetention time 6 hrs , sludge age 10days, under flow SS concentration = 15000mg/l, decay rate= 0.055 dayconcentration and the solids are 80% volatile.(k,, 20 = 0.24 /day), yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solidFind: - 1- MLSS (mg/l) 2- Recirculation ratio

Given data: Kd=0.055 day-1Q=600 m3/hrθc=10 daysS=20 mg/lXU=15000 mg/lultimate Bod (SU)=140…

Answered: Q2) A waste of 600 m*hr flow rate with…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

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Q2) A waste of 600 m*hr flow rate with an ultimate BODZ° = 140 mg/l is to be treated in an activated sludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor the detention time = 6 hrs , sludge age = 10days , under flow SS concentration = 15000mg/1 , decay rate = 0.055 day , yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solid concentration and the solids are 80% volatile.( ky, 20 = 0.24 /day) Find: - 1- MLSS (mg/l) 2- Recirculation ratio

Q2) A waste of 600 m/hr flow rate with an ultimate BOD20 = 140 mg/1 is to be treated in an activated
sludge process to yield an effluent of 20mg/l BOD5 and 25mg/ suspended solids. For the reactor the
detention time 6 hrs , sludge age 10days, under flow SS concentration = 15000mg/l, decay rate
= 0.055 day
concentration and the solids are 80% volatile.(k,, 20 = 0.24 /day)
, yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solid
Find: - 1- MLSS (mg/l) 2- Recirculation ratio

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