Q2) A waste of 600 m¥hr flow rate with an ultimate BOD2° = 140 mg/l is to be treated in an activated sludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor the detention time = 6 hrs , sludge age = 10days , under flow SS concentration = 15000mg/1 , decay rate = 0.055 day , yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solid concentration and the solids are 80% volatile.( k1,20 = 0.24 /day) Find: - 1- MLSS (mg/l) 2- Recirculation ratio _Y0.(5, -9 T 1+K,.6, V=006 Q2) A waste of 600 m?/hr flow rate with an ultimate BOD20 = 140 mg/l is to be treated in an activatedsludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor thedetention time = 6 hrs , sludge age 10days, under flow SS concentration = 15000mg/l, decay rate= 0.055 day, yield coefficient 0.65 , BOD of the effluent SS =60% of the suspended solidconcentration and the solids are 80% volatile.(k, 20 = 0.24 /day)Find: 1- MLSS (mg/l) 2- Recirculation ratioYO.(S. - S)QQ.XQr =X, - XX.V =V = Q.0cr =1+ Ka. OcC - Ce1|Q.C1+ 0.532V.F

Q = 600 m3hr y = .65 kd = .055 /day So = 140 mgl Se = 20 mgl θc= 10 days

Answered: Q2) A waste of 600 m/hr flow rate with…

Structural Analysis

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ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

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Q2) A waste of 600 m¥hr flow rate with an ultimate BOD2° = 140 mg/l is to be treated in an activated sludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor the detention time = 6 hrs , sludge age = 10days , under flow SS concentration = 15000mg/1 , decay rate = 0.055 day , yield coefficient = 0.65 , BOD of the effluent SS =60% of the suspended solid concentration and the solids are 80% volatile.( k1,20 = 0.24 /day) Find: - 1- MLSS (mg/l) 2- Recirculation ratio _Y0.(5, -9 T 1+K,.6, V=006

Q2) A waste of 600 m?/hr flow rate with an ultimate BOD20 = 140 mg/l is to be treated in an activated
sludge process to yield an effluent of 20mg/l BOD5 and 25mg/l suspended solids. For the reactor the
detention time = 6 hrs , sludge age 10days, under flow SS concentration = 15000mg/l, decay rate
= 0.055 day, yield coefficient 0.65 , BOD of the effluent SS =60% of the suspended solid
concentration and the solids are 80% volatile.(k, 20 = 0.24 /day)
Find: 1- MLSS (mg/l) 2- Recirculation ratio
YO.(S. - S)Q
Q.X
Qr =
X, - X
X.V =
V = Q.0c
r =
1+ Ka. Oc
C - Ce
1
|Q.C
1+ 0.532
V.F

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