Q1: Shaft subjected to the loadings in phase shown such that: T=0 N.m to 200 N.m M=-200 to 200 N.m The shaft has d1=60 mm, d2=40mm, r=8 mm, cold drawn, operating temp. 550 C, relaibility of the data 99.9%, Material Properties; out = 1260 MPa, Out=813 Mpa. Is the shaft fails for infinity life design? T м M d T

Q1: Shaft subjected to the loadings in phase shown such that: T=0 N.m to 200 N.m M=-200 to 200 N.m The shaft has d1=60 mm, d2=40mm, r=8 mm, cold drawn, operating temp. 550 C, relaibility of the data 99.9%, Material Properties; out = 1260 MPa, Out=813 Mpa. Is the shaft fails for infinity life design? T м M d T

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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TI=30NM, T2=155NM, T3=85NM and dBC=22mm. 12 010 T3 T2 T1 3-1892615112 D 010 b180106003- 1892615112 \dcp 1826151126 b180106003-18926 dBC B. `dAB b180100003-18926151126 In the figure above, torques TI, T2 and T3 are applied, respectively, to discs A, B and C on the shaft, which is fixed at point D. 3-1892815112s b180106003-18926 The diameters of the shaft segments are indicated in the figure and their values are given below (if they are required). Length of each segment on the shaft has the same value and is equal to L(AB)=L(BC)=L(CD)=400 mm. b180106003- 18926151126 Shear modulus of the material is 80 GPa. o-18926151126 b180108003-18926 Calculate the maximum shear stress g003-18926151126 003-18926 b18 on shaft segment BC. 010600s28151128 B A 46 MPa 60 MPа b180106003- 18926 b180106003- 1892615112 b180106003- 18928151126 38 MPa b180100003-1892615112 57 MPa b180106003- 18926151126 E b180108003-18928 31 MPа b180106003- 18926151126 b180106003- 18926151128 b180106003- 18928151126…
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% 09 assambly3.pdf -> 26 K7/p6 ---- Ø26 32N7/n6 4 Shaft 3 Shaft 2 Gear steel D26 1 steel D32 1 steel M5, N12 1 1 Gear steel M5, N50 1 N Name material of part Notes Q ترس اسطواني عدل الموديول =5 ع د استان الترس الكبير =N30 دائرة خطوة الترس الصغير Dp=75 mm عرص وجه السن F=3( m سمك جار الترس الكبير mm 10= قطر عمود الترس الكبير dsti=32m m قطر عمود الترم الصغير dr =26nm dao=56 mmall i ila المطلوب رسم المقطع الأمامي والمسقط الجاني ال لتر سين أعلاه Dpe 60 mm DG = 7= NG"m = 50 *S= 250 mm DoP= 60 +2*5= 70 mm DRP-60-2*1.12*S 48.8mm DoG= 250 +10 =260 DRG= 250- 21.12*5 238 8 mm Dhout= DRG-2h= 238.8-2*h(a+b)(10.6) 238.8-2*10,6-217.6 mm
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2. A 1020 CD steel shaft (Sy=390 MPa) is used to transmit 20 kW of power at 1200 rpm. There are no bending or axial loads on the shaft. It is desired to have a static factor of safety of 2 based on the Distortion Energy theory. Determine the minimum diameter needed for the shaft. Power, P= To Pure torsion, relationship between T and t Torsional stress
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1) A compression spring has square edge and ground ends. The total coil number of spring is 12 and Brinell Hardness number is HB=380. The free length of the spring is 200 mm. The spring is assembled into a machine by compressing, when the machine runs, the spring is compressed 6 mm- 40 mm 18 mm 100 mm. 10 mm a) Is the siring likely to buckled. b) Would this spring developed a permanent set if compressed solid? c) What is the critical frequency?