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Screws rotate at an ansular rate of n = 1720 28-6775463 603 The lead is 4 = 0.25 in, so the Linear speed of the press head it V = 28-67 × 0.25= 7.17 in/min F = 2500 Ibf /screw dm> 0-95 Secd: 1 cas(29/2) 21.033 TR = Torque threads- Fdm +fdm sech 2 dm-feseca = 2500X 1-875/0.2++π (0.05) (1.875)11033) 2 = 221-0 Ibf: in 5(1873(2)(1127) + Te = Torque of collar = 2+00 × 0.08 × 35 = 2 =150:in 2 · Trotal: 350+221.0= 57126f. in Iscrew Tmotor = 571(2) H = In = 20.04 Ibfain бохо-9 г- 63025 = 20.04 (1720) 63025 20.747 hP

Screws rotate at an ansular rate of n = 1720 28-6775463 603 The lead is 4 = 0.25 in, so the Linear speed of the press head it V = 28-67 × 0.25= 7.17 in/min F = 2500 Ibf /screw dm> 0-95 Secd: 1 cas(29/2) 21.033 TR = Torque threads- Fdm +fdm sech 2 dm-feseca = 2500X 1-875/0.2++π (0.05) (1.875)11033) 2 = 221-0 Ibf: in 5(1873(2)(1127) + Te = Torque of collar = 2+00 × 0.08 × 35 = 2 =150:in 2 · Trotal: 350+221.0= 57126f. in Iscrew Tmotor = 571(2) H = In = 20.04 Ibfain бохо-9 г- 63025 = 20.04 (1720) 63025 20.747 hP

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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How the sec (alpha) value is measured 29/2? Can you please describe the circled line in details.Thank you
Screws rotate at an ansular rate of n = 1720 28-6775463 603 The lead is 4 = 0.25 in, so the Linear speed of the press head it V = 28-67 × 0.25= 7.17 in/min F = 2500 Ibf /screw dm> 0-95 Secd: 1 cas(29/2) 21.033 TR = Torque threads- Fdm +fdm sech 2 dm-feseca = 2500X 1-875/0.2++π (0.05) (1.875)11033) 2 = 221-0 Ibf: in 5(1873(2)(1127) + Te = Torque of collar = 2+00 × 0.08 × 35 = 2 =150:in 2 · Trotal: 350+221.0= 57126f. in Iscrew Tmotor = 571(2) H = In = 20.04 Ibfain бохо-9 г- 63025 = 20.04 (1720) 63025 20.747 hP
Transcribed Image Text:Screws rotate at an ansular rate of n = 1720 28-6775463 603 The lead is 4 = 0.25 in, so the Linear speed of the press head it V = 28-67 × 0.25= 7.17 in/min F = 2500 Ibf /screw dm> 0-95 Secd: 1 cas(29/2) 21.033 TR = Torque threads- Fdm +fdm sech 2 dm-feseca = 2500X 1-875/0.2++π (0.05) (1.875)11033) 2 = 221-0 Ibf: in 5(1873(2)(1127) + Te = Torque of collar = 2+00 × 0.08 × 35 = 2 =150:in 2 · Trotal: 350+221.0= 57126f. in Iscrew Tmotor = 571(2) H = In = 20.04 Ibfain бохо-9 г- 63025 = 20.04 (1720) 63025 20.747 hP
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