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Q1: Insert the following numbers in order [26,12,48,30,10,50]. Then, draw how the tree looks like:
You may use BST simulation to visualize it, then take a snapshot.
Step by step
Solved in 2 steps with 1 images
- You can plot shapes in Python using line graphs in matplot lib by providing the coordinates of the vertices of the shapes as x, y pairs and using the matplotlib.pyplot.plot (i.e. plt.plot) function. Draw a triangle, square, pentagon, hexagon and heptagon. Note: Use symmetry, starting with the origin at (0,0), and set the distance from the origin to the vertex to be of length 1.0 (otherwise this becomes very complicated for some shapes).import tkinter as tkfrom tkinter import ttkroot = tk.Tk()root.title("Escape from the Maze")root.geometry("600x300")frame = ttk.Frame(root, padding="200 100 200 100")frame.pack(fill=tk.BOTH, expand=True)def click_button1(): root.title("Wrong way!")def click_button2(): root.destroy()button1 = ttk.Button(frame, text="Go Left", command=click_button1)button2 = ttk.Button(frame, text="Go Right", command=click_button2)button1.pack()button2.pack()root.mainloop() Refer to Code Example 18-1: Which code snippet adds the frame to the root window? a. root.mainloop() b. root = tk.Tk()root.title("Escape from the Maze")root.geometry("600x300") c. frame = ttk.Frame(root, padding="200 100 200 100")frame.pack(fill=tk.BOTH, expand=True) d. import tkinter as tkfrom tkinter import ttkTask 4: Matplotlib Import the plotting function by the command: import matplotlib.pyplot as plt Plotting multiple lines Compute the x and y coordinates for points on sine and cosine curves and plot them on the same graph using matplotlib. Add x and y labels to the graph as well. Note: Please provide PYTHON (ANACONDA) code for above task.
- Need to use numpy to create this graph. I have the following code but am unsure of how to graph the intersection points: import randomimport matplotlib.pyplot as pltimport numpy as npx4 = np.linspace(0,6*np.pi,200)plt.plot(x4,x4)plt.plot(x4,x4*np.sin(x4))1. In each iteration of a loop, generate a random number, and use it to determine some attribute of what is drawn in that iteration. For example, draw one shape multiple times in random locations and/or at random sizes OR 2. write a triply nested for loop to add even more complexity to your drawing than with a doubly nested loopCode Example 18-1import tkinter as tkfrom tkinter import ttkroot = tk.Tk()root.title("Escape from the Maze")root.geometry("600x300")frame = ttk.Frame(root, padding="200 100 200 100")frame.pack(fill=tk.BOTH, expand=True)def click_button1(): root.title("Wrong way!")def click_button2(): root.destroy()button1 = ttk.Button(frame, text="Go Left", command=click_button1)button2 = ttk.Button(frame, text="Go Right", command=click_button2)button1.pack()button2.pack()root.mainloop() Refer to Code Example 18-1: If the user clicks the Go Right button, what happens? a. The title of the root window changes to “Wrong way!”. b. The root window closes and the program exits. c. The frame expands to fill the entire window. d. Nothing because the function isn’t connected to the button.
- In Python, Create three plots in the same graph. grades = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83,65,85]}Java Given main(), complete the SongNode class to include the printSongInfo() method. Then write the Playlist class' printPlaylist() method to print all songs in the playlist. DO NOT print the dummy head node.For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print:20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() { const int SIZE_LIST = 4; vector<int> keysList(SIZE_LIST); vector<int> itemsList(SIZE_LIST); unsigned int i; for (i = 0; i < keysList.size(); ++i) { cin >> keysList.at(i); } for (i = 0; i < itemsList.size(); ++i) { cin >> itemsList.at(i); } /* Your solution goes here */ cout << endl; return 0;}