Q.2 Draw the combination of Diene and Dienophile that undergoes a Diels-Alder reaction to give the adduct shown on the left. a) H b) O OMe O OMe c) O Me Me Diene Dienophile Diene Dienophile Diene Dienophile
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- for part b, besides drawing the reaciton coordiate diagram, can you give. a quite detailed explanation about how do we know which curve corrresponds to A or B. i.e. how do we know A or B energy is higher ; whether theres energy differnce between reactant and products. thanks help with part b pleaseWhat is the resonanace for each molecule in second picture.The rate of a Diels-Alder reaction is favored by select all that apply electron withdrawing dienophile electron donating dienophile s-cis diene s-trans diene sdsdienophile
- Rank the following in order of increasingly exothermic heat of hydrogenation. Explain. A BWould you expect nitroethylene to be more or less reactive than ethylene in a Diels-Alder reaction? (Hint: Draw the resonance structures of nitroethylene.) Ethylene neither do Nitroethylene O Ethylene is more reactive than nitroethylene in Diels-Alder reaction O Nitroethylene is more reactive than ethylene in Diels-Alder reaction sameWould like help drawing out this mechanism step by step please. I need to know to how each step follows the other. Not one drawing with a million arrows please
- Draw the major product of the following Diels-Alder reaction. Show the product stereochemistry using wedged and dashed bonds. + 00 edit structure...Select the keyword or phrase that will best complete each sentence. Key terms: backside carbocation elimination frontside hyperconjugation inversion maintenance nucleophile product racemization stronger substitution weaker Alkyl halides undergo A orbital. reactions with Brønsted-Lowry bases. is a sp² hybridized and trigonal planar and contains a vacant p All SN2 reactions proceed with in attack of the nucleophile, resulting of configuration at a stereognic center. Spreading out charge by the overlap of an empty p orbital with an adjacent o bond is called Equilibrium favors the products of nucleophilic substitution when the leaving group is a base than the nucleophile. According the to Hammond postulate, the stability of the determines the rate of its formation. The formation of equal amounts of two enantiomeric products from a single starting material is called A is an electron-rich compound, which donates a pair of electrons to an electron deficient compound, forming a covalent bond.…Consider a traditional Diels Alder reaction noting it's methodology and synthetic tactical. Then propose an alternative, greener synthetic route to make the same product with near or same enantioselectivity.