Project #5 The purpose of this project is to get familiar with the programming language C to be able to leam the next lectures. The following Java program makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. Convert the program to a C program. Use the built-in function: malloc to dynamically allocate locations for variables: a and b. import java.util.Bandon; public class Main { public static void main(String[] aces){ int[) a; int[] b; Random r= new Random(Systen.CuCcentIimettiLLis()); int alsnsth - CextInt(10) + 90; 1/9; int blength - GDRxtInt(10) + 10; //2; while(alensth X blength !- e) alengthe+; Making aleosth divisible by bleosth a- new int[alsosth); b- new int(blengtb]; for(int i- e; &< dedeoeth: ++) a[4) - GDextint(10); ecintferwaod(a); for(int index = e; index < adegth: { for(int i- e;i < Budeorths ++) b[1] - a[indexei); Bcinteackwand( b); index + bulength: private static void gcinteackoard(int[] x) { for(int i = Kadength - 1; i >= e; i--) Sxsten.out.prins(*[3) + ", "); Susten.out.orintln(); private static void gcintfeoard(int[] x) { for(int i- e; i Kdength: i++) Sxsten.out.Rcint (x[A) +, "); Susten.out.println(); Answer:
Project #5 The purpose of this project is to get familiar with the programming language C to be able to leam the next lectures. The following Java program makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. Convert the program to a C program. Use the built-in function: malloc to dynamically allocate locations for variables: a and b. import java.util.Bandon; public class Main { public static void main(String[] aces){ int[) a; int[] b; Random r= new Random(Systen.CuCcentIimettiLLis()); int alsnsth - CextInt(10) + 90; 1/9; int blength - GDRxtInt(10) + 10; //2; while(alensth X blength !- e) alengthe+; Making aleosth divisible by bleosth a- new int[alsosth); b- new int(blengtb]; for(int i- e; &< dedeoeth: ++) a[4) - GDextint(10); ecintferwaod(a); for(int index = e; index < adegth: { for(int i- e;i < Budeorths ++) b[1] - a[indexei); Bcinteackwand( b); index + bulength: private static void gcinteackoard(int[] x) { for(int i = Kadength - 1; i >= e; i--) Sxsten.out.prins(*[3) + ", "); Susten.out.orintln(); private static void gcintfeoard(int[] x) { for(int i- e; i Kdength: i++) Sxsten.out.Rcint (x[A) +, "); Susten.out.println(); Answer:
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I am learning C for a class I am taking and a homework assignment asks us to makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. We need to use the function malloc to dynamically allocate locations for variables a and b. The full assignment is below. I am not too familiar with C and I don't know how to split the list into two arrays.
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