program Here we're looking for the string target, in the list list_of_words. def search_binary(list_of_words, target, debug_print=False): "*" Find and return an index of target in list_of_words # 1 and r represent the region of interest that we search over. # initially this is the whole of xs 1 - 0 r = len(list_of_words) while 1 < r: m = (1 + r) // 2 # The mid point of the interval if debug_print: print("Interval[{0}:{1}](size={2}), probed='{3}', target='{4}'" .format (1, r, r-1, list_of_words[m], target)) if target < list_of_words[m][0]: r - m elif target > list_of_words[m][@]: 1 - m+1 else: assert target == list_of_words[m][0] return list_of_words[m][1] return -1 What has to be true about list_of_words in order for this function to find the index of the target word? You might want o look at Lecture 17 for reference if this seems mysterious. Is this search function fast? Can you explain why?

program Here we're looking for the string target, in the list list_of_words. def search_binary(list_of_words, target, debug_print=False): "*" Find and return an index of target in list_of_words # 1 and r represent the region of interest that we search over. # initially this is the whole of xs 1 - 0 r = len(list_of_words) while 1 < r: m = (1 + r) // 2 # The mid point of the interval if debug_print: print("Interval[{0}:{1}](size={2}), probed='{3}', target='{4}'" .format (1, r, r-1, list_of_words[m], target)) if target < list_of_words[m][0]: r - m elif target > list_of_words[m][@]: 1 - m+1 else: assert target == list_of_words[m][0] return list_of_words[m][1] return -1 What has to be true about list_of_words in order for this function to find the index of the target word? You might want o look at Lecture 17 for reference if this seems mysterious. Is this search function fast? Can you explain why?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

10. Consider the following program, implementing binary search to look for a word in a list of words:
Here we're looking for the string target, in the list list_of_words.
def search_binary(list_of_words, target, debug_print=False):
"*" Find and return an index of target in list_of_words
# 1 and r represent the region of interest that we search over.
# initially this is the whole of xs
1 = 0
r = len(list_of_words)
while 1 < r:
m = (1 + r) // 2 # The mid point of the interval
if debug_print:
print("Interval[{0}:{1}](size={2}), probed='{3}', target='{4}'"
.format(1, r, r-1, list_of_words[m], target))
if target < 1list_of_words[m][0]:
r = m
elif target > list_of_words[m][@]:
1 = m+1
else:
assert target ==
list_of_words[m][®]
return list_of_words[m][1]
return
1
What has to be true about list_of_words in order for this function to find the index of the target word? You might want
to look at Lecture 17 for reference if this seems mysterious. Is this search function fast? Can you explain why?

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