Implement the following function. Hint: You should use a dictionary. def word_pattern (pattern: str, words: List [str]) -> bool: "Given a pattern and a word list, determine if the word list follows the same pattern. That is to say, ensure that pattern [j] == pattern [k] only when words [j] == words [k] pattern [j] != pattern [k] means words [j] != words [k] Precondition: Assume pattern is all lowercase letters. >>> word_pattern ('aaaa', ['cat', 'cat', 'cat', 'cat']) Tuu and

Implement the following function. Hint: You should use a dictionary. def word_pattern (pattern: str, words: List [str]) -> bool: "Given a pattern and a word list, determine if the word list follows the same pattern. That is to say, ensure that pattern [j] == pattern [k] only when words [j] == words [k] pattern [j] != pattern [k] means words [j] != words [k] Precondition: Assume pattern is all lowercase letters. >>> word_pattern ('aaaa', ['cat', 'cat', 'cat', 'cat']) Tuu and

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Implement a list of employees using a dynamic array of strings.Your solution should include functions for printing list, inserting and removingemployees, and sorting lists (use Bubble sort in C++ language).Keep list of employees sorted within the list after insertion.See the following example:How many employees do you expect to have?5 (Carriage Return)Menu :1 . Print full list of employees2 . Insert new employee3 . Remove employee from list0 . Exit2 (Carriage Return)Input name of new employee : MikeMenu :1 . Print full list of employees2 . Insert new employee3 . Remove employee from list0 . Exit1(Carriage Return)1 . MaryMenu :1 . Print full list of employees2 . Insert new employee3 . Remove employee from list0 . Exit
def sort and_pop(x: list, i: int) -> list: x.sort() return x.pop(i) # Dan's code lst = [23, 17, 3, 13, 11, 5, 7, 2, 19, 1] lst = sort_and_pop(lst, 5) lst = sort_and_pop(lst, 2) II I| || If you run this code, you'll find that it produces an error. Surprise! According to the type contract, Dan's Code should work. But it doesn't, because the function type contract has faulty type annotations. Correct the function type contract so that it's clear from the type contract that Dan's code will not work. (Dan's Code will and should remain an incorrect use of the function!) TODO: Write a new type contract"" "
def print_categories(main_list): for i in all_categories: main_list = all_categories.split() print(i,":",all_categories[i]) return "" """ Given a list of lists, for each list stored in main_list, output its contents as follows: f"{index of category}. {item[0]} - {item[1]}%". note that indexing must start at 1 for the first item, not 0, which is first item's actual index in main_list. If `main_list` is empty, the function prints "There are no categories." Returns the number of categories.
struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };
Alert dont submit AI generated answer. please explain in details. Please print fixlist function so it would print out both lists a = [1, 5, 3, 6] b = [3, 5, 3 ,2, 4, 6, 8, 5, 2] def printList(list): for i in range(9): print(list[i]) print("End of List" print list(a) printList(b) Expected output: 1 5 3 6 End of List 3 5 3 2 4 6 8 5 2
def reverse_list (1st: List [Any], start: int, end: int) -> None: """Reverse the order of the items in list , between the indexes and (including the item at the index). If start or end are out of the list bounds, then raise an IndexError. The function must be implemented **recursively**. >>> lst ['2', '2', 'v', 'e'] >>>reverse_list (lst, 0, 3) >>> lst ['e', 'v', 'i', '2'] >>> lst [] >>>reverse_list (lst, 0, 0) >>> lst [0] >>> Ist = [] >>> reverse_list (lst, 0, 1) Traceback (most recent call last): IndexError #1 #1
python Using try/except block and a for loop
Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1
Implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value. Ex: If the input is: hey hi Mark hi mark the output is: Mark: 1 hey: 1 hi: 2 mark: 1
Complete the doctring.def average_daily_temp(high_temps: List[int], low_temps: List[int]) -> List[float]: """high_temps and low_temps are daily high and low temperatures for a series of days. Return a new list of temperatures where each item is the daily average. Precondition: len(high_temps) == len(low_temps) >>> average_daily_temp([26, 27, 27, 28, 27, 26], [20, 20, 20, 20, 21, 21]) [23.0, 23.5, 23.5, 24.0, 24.0, 23.5] """
Assume, you have been given a dictionary where the keys present the name of the father and the value is a list of names of the sons of that person. For example A has 3 sons namely X, Y, and Z. Again X has three sons namely E, F, and G. So, A is the grandfather of E, F, and G. family = {"A" : ["X", "Y", "Z"], "B": ["M", "N"], "W" : ["A", "B"], "X" : ["E", "F", "G"]} You need to write a code which takes an input and prints the names of all his grandsons in the format shown in output samples. If he does not have any grandchildren just print “Get your sons married first! Wanna_be_grandpa!!” You can assume the input will always be a key from the dictionary. But we will check your code with a different dictionary. So do not write a code for this particular dictionary only. Enter Assume, you have been given a dictionary where the keys present the name of the father and…
In python make a function with the parameter of a dict[str, str] the function will simply invert the dictionary do not use .get, .item, .values, or import builtins If you encounter more than one of the same key when trying to invert the key and value, raise a keyerror for example ['john': 'white', 'garcia': 'white'], should trigger the raise KeyError call