erator to get and set list elements (e.g., lst[i] and lst[i] = a) • the in and not in operators (e.g., a in lst) • the list concatenation operator (e.g., lst1 + lst2) • the list replication operator (e.g., lst * n or n * lst) • Python's built-in len, min and max functions, unless otherwise noted. Your solutions cannot use: • list slicing (e.g., lst[i : j] or (lst[i : j] = t) • the del statement (e.g., del lst[0])
Automated testing is required
Your solutions can use:
• the [] operator to get and set list elements (e.g., lst[i] and lst[i] = a)
• the in and not in operators (e.g., a in lst)
• the list concatenation operator (e.g., lst1 + lst2)
• the list replication operator (e.g., lst * n or n * lst)
• Python's built-in len, min and max functions, unless otherwise noted.
Your solutions cannot use:
• list slicing (e.g., lst[i : j] or (lst[i : j] = t)
• the del statement (e.g., del lst[0])
• Python's built-in reversed and sorted functions.
• any of the Python methods that provide list operations, e.g., sum, append, clear, copy, count, extend, index, insert, pop, remove, reverse and sort
• list comprehensions
using python language Use the function design recipe to develop a function named max_min. The function takes a list of integers. (Assume that the list has at least two integers). The function returns the largest and smallest elements in the list as a string. For example, when the function's argument is [10, 3, 5, 6], the function returns “max = 10 and min = 3”.
For this exercise, your function is not permitted to call Python's min and max functions. It is true that Python offers a very elegant and efficient solution (a version shown below) but in this exercise, we want you to practice writing loops.
Code:
def has22(a):
for i in range(len(a)-1):
if a[i] == 2 and a[i+1] == 2:
return True
return False
print(has22([1, 2, 2, 3]))
print(has22([4, 2, 3, 2]))
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