5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexList

5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexList

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

5. The following function indexCounter aims to find and return all the indices of the
element x in a list L. if x is not in the list L, return an empty list. However, the
implementation has a flaw, so that many times it will return error message. Can you fix the
flaw?
def indexCounter(L, x):
indexList
[]
startIndex = 0
while startIndex < len(L):
indexList.append (L.index (x, startIndex))
startIndex = L.index (x, startIndex) + 1
return indexList

Expert Solution

Program –

def indexCounter(L, x):

indexList = []

startIndex = 0

while startIndex < len(L):

try:

indexList.append(L.index(x, startIndex))

startIndex = L.index(x, startIndex) + 1

except ValueError as e:

break

return indexList

L = [1, 2, 3, 4, 5, 1, 6]

print (indexCounter(L, 1))

Output –

Step by step

Solved in 3 steps with 1 images

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