10. Consider the following program, implementing binary search to look for a word in a list of words: Here we're looking for the string target, in the list list of words. def search_binary(list of_words, target, debug_print-False): "** Find and return an index of target in list_of_words # 1 and r represent the region of interest that we search over. # initially this is the whole of xs 1 - 0 r = len(list_of_words) while 1 < r: m = (1 + r)// 2 # The mid point of the interval if debug_print: print("Interval [{0}:{1}](size-{2}), probed=D'{3}', target-(4}" .format (1, r, r-1, list_of_words[m], target)) if target < list_of_words[m][0]: r = m elif target > list_of_words[m][0]: 1 - m+1 else: assert target == list_of_words[m][0] return list_of_words[m][1] return What has to be true about list of words in order for this function to find the index of the target word? You m to look at Lecture 17 for reference if this seems mysterious, Is this search function fast? Can you explain why

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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10. Consider the following program, implementing binary search to look for a word in a list of words:
Here we're looking for the string target, in the list list_of_words.
def search_binary(list_of_words, target, debug_print-False):
"*" Find and return an index of target in list_of_words
# 1 and r represent the region of interest that we search over.
# initially this is the whole of xs
1- 0
r = len(list_of_words)
while 1 < r:
m = (1 + r) // 2 # The mid point of the interval
if debug_print:
print("Interval[{0}:{1}](size={2}), probed='{3}', target="{4}"
- format(1, r, r-1, list_of_words[m], target))
if target < list_of_words[m][0]:
elif target > list_of_words[m][0]:
1 - m+1
else:
assert target ==
list of_words[m][@]
return list_of_words[m][1]
return
-1
What has to be true about list of_words in order for this function to find the index of the target word? You might want
to look at Lecture 17 for reference if this seems mysterious. Is this search function fast? Can you explain why?
Transcribed Image Text:10. Consider the following program, implementing binary search to look for a word in a list of words: Here we're looking for the string target, in the list list_of_words. def search_binary(list_of_words, target, debug_print-False): "*" Find and return an index of target in list_of_words # 1 and r represent the region of interest that we search over. # initially this is the whole of xs 1- 0 r = len(list_of_words) while 1 < r: m = (1 + r) // 2 # The mid point of the interval if debug_print: print("Interval[{0}:{1}](size={2}), probed='{3}', target="{4}" - format(1, r, r-1, list_of_words[m], target)) if target < list_of_words[m][0]: elif target > list_of_words[m][0]: 1 - m+1 else: assert target == list of_words[m][@] return list_of_words[m][1] return -1 What has to be true about list of_words in order for this function to find the index of the target word? You might want to look at Lecture 17 for reference if this seems mysterious. Is this search function fast? Can you explain why?
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