2.. please choose the correct answer and show your complete solution Circuit diagramVPhasor diagramIRd. 12.54<55.43° Q, e. P = 225 Wa. IR = 3<0° A, IL = 4.0<-90° Aa. IR = 3<0° A, IL = 4.77<-90° Ad. 11.32<61.39° Q, e. P = 180 Wc. phase angle or power factor angle= 61.39°, or power factor =cos(61.39°) = 0.479 laggingd. 13.32<57.83° Q, e. P = 224.82 Wc. phase angle or power factor angle= 57.83°, or power factor =cos (57.83°) = 0.532 laggingb. l-total = 5<-53.13° Ac. phase angle or power factor angle= 53.13°, or power factor =cos(53.13°) = 0.60 laggingb. l-total = 6.26<-61.39° ANone of the aboveb. l-total = 5.63<-57.83° Aa. IR 3<0° A, IL = 5.5<-90° A A 20 Q resistor is connectedin parallel with an inductance of2.387 mH (2.387E-03 H) across a 60V, 1 kHz (1E+03 Hz) supply. Calculate(a) the current in each branch, (b) thesupply current, (c) the circuitphase angle, (d) the circuitimpedance and (e) thepower consumed.Solution: Using PhasorsFirst, assume the supply voltage isRMS and as reference at angle 0.Vrms = 60<0° Va. Calculate the branch currents, IRand ILIR = Vrms/R = 60<0° V/20 Q = 3<0° AIL = Vrms/XL = 60<0° V/(2*1E+03Hz*2.387E-03 H) = 4.0<-90° Ab. l-total, vector sum of IR and ILI-total = 3<0° A + 4.0<-90° A =5<-53.13° Ac/d. You may determine first theimpedance, ZZ = Vrms / I-total = 60<0°V/ 5<-53.13° A = 12<53.13° 0the angle of impedance indicates thephase angle between the voltage andthe current, answer is = 53.13°. It isalso positive so the power factor islagging (see the phasor diagram, V isat zero angle, I is at -53.13°, lookingat counter clockwise motion of V and1).Power factor = cos = cos(53.13°) =0.60 lagginge. power consumed, true power P =|Vrms|*|Irms|*cosP = (60V)(5A)cos(53.13°) = 180 WorP = |IR|^2*R = (3^2) *20 Q = 180 Wremember the average power, P forreactances XL and Xc are zero.Problem: A 25 Q resistor isconnected in parallel with aninductance of 2.5 mH across a Vrms= 75<0° V, f = 1 kHz supply. Calculate(a) the current in each branch, (b) thesupply current, (c) the circuitphase angle, (d) the circuitimpedance and (e) thepower consumed.

Answered: Image /qna-images/answer/4909a150-acdc-4272-ba8e-e326bdc3d874.jpg

Problem: A 250 resistor is connected inductance in parallel with an of 2.5 mH across a Vrms = 75<0° V, f = 1 kHz supply. Calculate (a) the current in each branch, (b) the supply current, (c) the circuit phase angle, (d) the circuit impedance and (e) the power consumed.

Problem: A 250 resistor is connected inductance in parallel with an of 2.5 mH across a Vrms = 75<0° V, f = 1 kHz supply. Calculate (a) the current in each branch, (b) the supply current, (c) the circuit phase angle, (d) the circuit impedance and (e) the power consumed.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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