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Problem 3. Rework Problem 1 above (using an MLVSS concentration of 3,000 mg/L), but for a PFR with a recycle ratio = 0.50. Also use the same Q == 12,960 m³/d, So = 84 mg BOD5/L, same S corresponding to the effluent standard of 30 mg BOD5/L and 30 mg/L suspended solids (with BOD5 of effluent solids = 63% of suspended solids concentration), Ks = 100 mg BOD5/L, ka = 0.05 d¨¹, μm= 2.5 d¹, Y 0.5 mg VSS/mg BOD5. = µm=

Problem 3. Rework Problem 1 above (using an MLVSS concentration of 3,000 mg/L), but for a PFR with a recycle ratio = 0.50. Also use the same Q == 12,960 m³/d, So = 84 mg BOD5/L, same S corresponding to the effluent standard of 30 mg BOD5/L and 30 mg/L suspended solids (with BOD5 of effluent solids = 63% of suspended solids concentration), Ks = 100 mg BOD5/L, ka = 0.05 d¨¹, μm= 2.5 d¹, Y 0.5 mg VSS/mg BOD5. = µm=

Principles of Geotechnical Engineering (MindTap Course List)
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter8: Seepage
Section: Chapter Questions
Problem 8.12P
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Problem 3. Rework Problem 1 above (using an MLVSS concentration of 3,000 mg/L), but for a PFR with a recycle ratio = 0.50. Also use the same Q == 12,960 m³/d, So = 84 mg BOD5/L, same S corresponding to the effluent standard of 30 mg BOD5/L and 30 mg/L suspended solids (with BOD5 of effluent solids = 63% of suspended solids concentration), Ks = 100 mg BOD5/L, ka = 0.05 d¨¹, μm= 2.5 d¹, Y 0.5 mg VSS/mg BOD5. = µm=
Transcribed Image Text:Problem 3. Rework Problem 1 above (using an MLVSS concentration of 3,000 mg/L), but for a PFR with a recycle ratio = 0.50. Also use the same Q == 12,960 m³/d, So = 84 mg BOD5/L, same S corresponding to the effluent standard of 30 mg BOD5/L and 30 mg/L suspended solids (with BOD5 of effluent solids = 63% of suspended solids concentration), Ks = 100 mg BOD5/L, ka = 0.05 d¨¹, μm= 2.5 d¹, Y 0.5 mg VSS/mg BOD5. = µm=
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