Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m= 0.0065 kg, while that of the block is M= 1.02 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 0.95 m above its initial height. Neglect air resistance. Part (a) Enter an expression for the speed of the block/bullet system immediately after the collision in terms of defined quantities and g. Expression ツー Select from the variables below to write your expression. Note that all variables may not be required. B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (b) Find the speed of the block/bullet system, in meters per second, immediately after the collision. Numeric : Anumeric value is expected and not an expression. ツー Part (c) Enter an expression for the initial speed of the bullet in terms of defined quantities and g. Expression : Vi Select from the variables below to write your expression. Note that all variables may not be required. B, y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (d) Find the initial speed of the bullet, in meters per second. Numeric : A numeric value is expected and not an expression. Vi Part (e) Find the initial kinetic energy of the bullet, in joules. Numeric : Anumeric value is expected and not an expression. KE¡ = Part (f) Enter an expression for the kinetic energy of the block/bullet system immediately after the collision, in terms of defined quantities and g. Expression : KEf = Select from the variables below to write your expression. Note that all variables may not be required. B. Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (g) Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet. Numeric : Anumeric value is expected and not an expression. KEÇKE;(%) =

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11th Edition
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Chapter1: Units, Trigonometry. And Vectors
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Linear Momentum Q2: Please answer all parts with reasoning and explain step by step in detail (even if minor).
Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in
the block. The bullet's mass is m = 0.0065 kg, while that of the block is M = 1.02 kg. After the collision the block/bullet system
swings and reaches a maximum height of h = 0.95 m above its initial height. Neglect air resistance.
Part (a) Enter an expression for the speed of the block/bullet system immediately after the collision in terms of defined quantities and g.
Expression :
Select from the variables below to write your expression. Note that all variables may not be required.
B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S
Part (b) Find the speed of the block/bullet system, in meters per second, immediately after the collision.
Numeric : A numeric value is expected and not an expression.
Part (c) Enter an expression for the initial speed of the bullet in terms of defined quantities and g.
Expression
Vi =
Select from the variables below to write your expression. Note that all variables may not be required.
В, у, ө, b, с, d, g, h, j, k, m, M, п, Р, S
Part (d) Find the initial speed of the bullet, in meters per second.
Numeric : Anumeric value is expected and not an expression.
Vi =
Part (e) Find the initial kinetic energy of the bullet, in joules.
Numeric : Anumeric value is expected and not an expression.
KE
Part (f) Enter an expression for the kinetic energy of the block/bullet system immediately after the collision, in terms of defined quantities and g.
Expression :
KEf=
Select from the variables below to write your expression. Note that all variables may not be required.
В, у, Ө, b, с, d, g, h, j, k, m, M, n, P, S
Part (g) Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial
kinetic energy of the bullet.
Numeric : A numeric value is expected and not an expression.
KEÇKE;(%) =
Transcribed Image Text:Problem 2: A bullet is fired horizontally into an initially stationary block of wood suspended by a string and remains embedded in the block. The bullet's mass is m = 0.0065 kg, while that of the block is M = 1.02 kg. After the collision the block/bullet system swings and reaches a maximum height of h = 0.95 m above its initial height. Neglect air resistance. Part (a) Enter an expression for the speed of the block/bullet system immediately after the collision in terms of defined quantities and g. Expression : Select from the variables below to write your expression. Note that all variables may not be required. B, Y, 0, b, c, d, g, h, j, k, m, M, n, P, S Part (b) Find the speed of the block/bullet system, in meters per second, immediately after the collision. Numeric : A numeric value is expected and not an expression. Part (c) Enter an expression for the initial speed of the bullet in terms of defined quantities and g. Expression Vi = Select from the variables below to write your expression. Note that all variables may not be required. В, у, ө, b, с, d, g, h, j, k, m, M, п, Р, S Part (d) Find the initial speed of the bullet, in meters per second. Numeric : Anumeric value is expected and not an expression. Vi = Part (e) Find the initial kinetic energy of the bullet, in joules. Numeric : Anumeric value is expected and not an expression. KE Part (f) Enter an expression for the kinetic energy of the block/bullet system immediately after the collision, in terms of defined quantities and g. Expression : KEf= Select from the variables below to write your expression. Note that all variables may not be required. В, у, Ө, b, с, d, g, h, j, k, m, M, n, P, S Part (g) Calculate the ratio, expressed as a percent, of the kinetic energy of the block/bullet system immediately after the collision to the initial kinetic energy of the bullet. Numeric : A numeric value is expected and not an expression. KEÇKE;(%) =
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