Points A [at (3, 6)m] and B [at (8, -3)m] are in a region where the electric field is given by Ē = 4x²î +3y¡ N/C. What is the potential difference VB - VA? Use point A as the final coordinate and point B as the initial coordinate, i.e., going from B to A.
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- A wire having a uniform linear charge density A 3 nC/m, is bent into the shape shown in :the figure. If R=5 cm, the electric potential (in V) at point O is 2R 2R 192.1 O 144.1 O 96.1 O 240.2 48.0 OProblem 7: The electric potential in a certain region varies with position as V(x) = ax? - bx + c, where a = 3.1 V/m2, b = 14 V/m, and c = 13.5 V. Part (a) Find the electric field vector E in this region in terms of the given variables. Be sure to include a unit vector for direction. E = | Y 7 8 9. НOME i j b ↑^ AL 4 5 6 a d. e 1 3 + END P S X VO BACKSPACE CLEAR DEL Submit Hint Feedback I give up! Submission History All Date times are displayed in Eastern Standard Time Red submission date times indicate late work. Date Time Answer Hints Feedback · Part (b) What is the magnitude of the electric field, in volts per meter, at x = 1.0 m? · Part (c) What is the direction of the electric field at x =1.0 m? Part (d) What is the magnitude of the electric field, in volts per meter, at x = 5.0 m? Part (e) What is the direction of the electric field at x = 5.0 m?A region of space contains an electric potential given by V(x,y,z) = 4x2y – 2z + 5x3yz2. Determine the componentsand the magnitude of the electric field at the point (1, 5, 0).
- PLEASE ONLY ANSWER PARTS D & E A proton is located at the origin, and a second proton is located on the x-axis at x1 = 5.24 fm (1 fm = 10−15 m). (a) Calculate the electric potential energy associated with this configuration. J(b) An alpha particle (charge = 2e, mass = 6.64 ✕ 10−27 kg) is now placed at (x2, y2) = (2.62, 2.62) fm. Calculate the electric potential energy associated with this configuration. J(c) Starting with the three particle system, find the change in electric potential energy if the alpha particle is allowed to escape to infinity while the two protons remain fixed in place. (Throughout, neglect any radiation effects.) J(d) Use conservation of energy to calculate the speed of the alpha particle at infinity. m/s(e) If the two protons are released from rest and the alpha particle remains fixed, calculate the speed of the protons at infinity. m/sThe electrostatic potential in all space is given here as a function of x, y and z. Find the electric field Ē(x.y,z) function and express your answer using unit vectors. V(x,y,z)= 4πεο 4 TE, Jx + y² +(z-d)*A uniform electric field of magnitude 350 V/m is directed in the negative y direction as shown in the figure below. The coordinates of point are (-0.550, -0.400) m, and those of point Bare (0.200, 0.850) m. Calculate the electric potential difference VB - VA using the dashed-line path. V TE x
- 15V IDV In the attached pic, equipotential lines with their electric potential values are given 1. Draw the electric field vector at each of the points A, B & C 2. Calculate the change in Electrical Potential Energy when a proton (with positive charge +e) moved fromAn electrostatic field is given by E = a(x + y) ex+ a(x+y) ẹy, where a is a constant. Determine the electrostatic potential difference AV between (x, y, z) = (L, L, 0) and the origin.A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x 80.0cm, y= 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y%3D 80.0 cm, carrying the same amount of charge with the same uniform density. At the same point P, the pair of filaments creates potential: 1. greater than 200 V 2. 200 V. 3. 100 V. 4. between 0 and 200 V 5. 0. . -1
- The electric potential from an elementary electric dipole located at the origin is given by the expression Þ(r) = p'r/(4TE,r³) where p is the electric dipole moment vector. Show that the corresponding electric field is given by the expression E = -VO = (3 p'r-hat r-hat - p)/(4tE,r³) where r-hat is the unit vector in the direction of the vector r.Two large (treat as infinite) parallel conducting plates are charged to t Q as shown by the battery. A proton is released from rest at point A and is measured to be moving with a speed v, = 2 x 105 m/s when at point B. The right plate is then moved closer to the left as shown in the %3D X X rightmost figure. The experiment is repeated. What will be the speed of the proton at point B? A) Greater B) Smaller C) Equal D) Impossible to determinePoint charges qA = 6.6 nC is located at (0, 0) and qB = -3.0 nC is located at (5.00 m, 0). What is the electric potential at point P (2.00 m, 0), in Volts? 1.00 nC = 1.00 × 10-9 C. Use K = 9.00 × 109 N·m2/C2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.