The electric potential Vin the space between two flat parallel plates 1 and 2 is given (in volts) by V = 1200x², where x (in meters) is the perpendicular distance from plate 1. At x = 1.1 cm, (a) what is the magnitude of the electric field and (b) is the field directed toward or away from plate 1?

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Chapter1: Units, Trigonometry. And Vectors
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The electric potential Vin the space between two flat parallel plates 1 and 2 is given (in volts) by V = 1200x², where x (in meters) is
the perpendicular distance from plate 1. At x = 1.1 cm, (a) what is the magnitude of the electric field and (b) is the field directed
toward or away from plate 1?
(a)
i
N/C
(b)
>
Transcribed Image Text:The electric potential Vin the space between two flat parallel plates 1 and 2 is given (in volts) by V = 1200x², where x (in meters) is the perpendicular distance from plate 1. At x = 1.1 cm, (a) what is the magnitude of the electric field and (b) is the field directed toward or away from plate 1? (a) i N/C (b) >
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(a)Given that potential, V=1200X2 VoltsThen electric field, E=-dVdXE=-d(1200X2)dXE=-1200×2X=-2400X............(1)put, X=1.1×10-2m in equation (1) we get electric field,E=-2400×1.1×10-2=-26.4 V/m (-ve sign showsthe direction of field between the plates so need to put)so,E=26.4 V/m

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