## Understanding Electric Fields with Parallel Plates### Problem DescriptionA proton enters the uniform electric field produced by two charged square plates. The plates carry charges $ +Q $ and $ -Q $, where the magnitude $ Q = 1.3 \, \mu C $. The speed of the proton when it enters the region between the plates is $ 0.5 \times 10^7 \, \text{m/s} $.#### Diagram Details:- The separation between the plates is shown as 12.0 cm.- The electric field is depicted with arrows pointing from the positive plate to the negative plate, indicating the direction of the field.- The proton enters from the left and is deflected downward as it passes through the field.### Questions**a. Calculate the Magnitude of the Electric Field**Assume that the plates are close enough to be treated as "infinite" for the purposes of calculating the electric field. Use the formula to determine the electric field $ E $ between the plates.\[ E = \, \_\_\_\_ \, \text{N/C}. \]**b. Calculate the Deflection of the Proton**Determine the distance $ d $ that the proton has been deflected downward when it exits the region between the plates. Consider only the influence of the electrostatic force.\[ d = \, \_\_\_\_ \, \text{cm}. \]### GuidanceTo solve these problems, use the known physical principles and formulas related to electric fields and forces on charges. For help or to check your understanding, feel free to **Message Instructor** or explore the **Course Chat**.**Submit your Answers** when you are ready.

We are given the amount of charge on plates. The plates used are square plates. The electric field…

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