Below is a set up with 2 charged particles -> q1 and a proton. They are a distance yapart (see the image below). The proton is released from rest and its acceleration a ismeasured. Below the image you will find what the variables are for your problem.y axisprotonq1a = (4.09x10^6) m/s² (Acceleration of the proton after it is released from rest)= (2.840x10^-2) mFind the charge of q1 for this set up. You can ignore other forces (like gravity) for thepurposes of this calculation.If the charge is negative, make sure to include that in the answer.Your answer should include:3 significant figuresUnits with your answerNote: Your answer is assumed to be reduced to the highest power possible.Your Answer:х10Answerunits

first charge = q1second particle = proton charge on proton = +1.6×10-19 C distance between two…

Below is a set up with 2 charged particles -> q1 and a proton. They are a distance y apart (see the image below). The proton is released from rest and its acceleration a is measured. Below the image you will find what the variables are for your problem. у axis proton y q1 a = (4.09x10^6) m/s² (Acceleration of the proton after it is released from rest) y = (2.840x10^-2) m Find the charge of q1 for this set up. You can ignore other forces (like gravity) for the purposes of this calculation. If the charge is negative, make sure to include that in the answer. Your answer should include: 3 significant figures Units with your answer Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: х10 Answer units

Below is a set up with 2 charged particles -> q1 and a proton. They are a distance y apart (see the image below). The proton is released from rest and its acceleration a is measured. Below the image you will find what the variables are for your problem. у axis proton y q1 a = (4.09x10^6) m/s² (Acceleration of the proton after it is released from rest) y = (2.840x10^-2) m Find the charge of q1 for this set up. You can ignore other forces (like gravity) for the purposes of this calculation. If the charge is negative, make sure to include that in the answer. Your answer should include: 3 significant figures Units with your answer Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: х10 Answer units

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter2: Vectors

Section: Chapter Questions

Problem 70P: (a) If AF=BF , can we conclude A=B ? (b) If AF=BF , can we conclude A=B ? (c) If FA=BF , can we...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Below is a set up with 2 charged particles -> q1 and a proton. They are a distance y
apart (see the image below). The proton is released from rest and its acceleration a is
measured. Below the image you will find what the variables are for your problem.
y axis
proton
q1
a = (4.09x10^6) m/s² (Acceleration of the proton after it is released from rest)
= (2.840x10^-2) m
Find the charge of q1 for this set up. You can ignore other forces (like gravity) for the
purposes of this calculation.
If the charge is negative, make sure to include that in the answer.
Your answer should include:
3 significant figures
Units with your answer
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
х10
Answer
units

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